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慕后端3277080 的学生作业：
#include enum COLOR { red = 1, green = 2, yellow, blue, black, }; int main() { int col; //要求用户从键盘输入数据存放到col中。 printf("please input data :"); scanf("%d",&col); //根据col输入的值，来输出对应的颜色。 switch(col) { case red: printf("col is red!\n"); break; case green: printf("col is green!\n"); break; case yellow: printf("col is yellow!\n"); break; case blue: printf("col is blue!\n"); break; case black: printf("col is black!\n"); break; } }
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慕后端3277080 的学生作业：
#include typedef struct { unsigned char Red; unsigned char Green; unsigned char Blue; }RGB_t; typedef union { RGB_t rgb; unsigned int value; }PIX_t; int main() { // 1. 定义一个PIX_t类型的变量，然后定义三原色分别为0X11、0X22、0X33 PIX_t color; color.rgb.Red = 0x11; color.rgb.Green = 0x22; color.rgb.Blue = 0x33; // 2. 不做任何处理，直接打印value printf("value = %#x\n",color.value); // 3. 观察结果 }
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慕后端3277080 的学生作业：
#include struct student { char name[20]; int id; int score; }st1 = {"jack",1,100}; int main(int argc,const char *argv[]) { struct student st[3] = { {"rose",2,70}, {"lilei",3,60}, {"hmm",4,50} }; int id; int i = 0; //1.输出st1整个信息 printf("name = %s,id=%d,score = %d\n",st1.name,st1.id,st1.score); //2.输出st中3个的信息 for(i = 0;i
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