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行转列 cross join查看全部
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先需要把mobile列通过分隔字符串转成行 再通过group by having方式删除 再通过group by concat 转换回来 再与原表关联更新查看全部
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利用group by 和having从句查找重复数据 select user_name,count(*) form user1_test group by user_name having count(*)>1 删除重复数据，保留重复数据中ID最大的 delete a from user1_test a join ( select user_name,count(*),max(id) as id from user1_test group by user_name having count(*)>1 ) b on a.user_name = b.user_name where a.id<b.id查看全部
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使用存储过程生成唯一订单号，每秒中可生成1千个查看全部
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优先选择系统提供的序列号生成方式 mysql的auto_increment的方式如果使用事务回滚会产生空洞情况查看全部
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select user_name, case when c.id=1 then 'arms' when c.id=2 then 'clothing' when c.id=3 then 'shoe' end as equipment, coalesce(case when c.id=1 then arms end, case when c.id=2 then clothing end, case when c.id=3 then shoe end) as eq_name from user1 a join user1_equipment b on a.id=b.user_id cross join tb_sequence c where c.id<=3 order by user_name;查看全部
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select * from ( select sum(kills) as '孙悟空' from user1 a join user_kills b on a.id = b.use_id and a.user_name='孙悟空' ) a cross join ( select sum(kills) as '猪八戒' from user1 a join user_kills b on a.id = b.use_id and a.user_name='猪八戒' ) b cross join( select sum(kills) as '沙僧' from user1 a join user_kills b on a.id = b.use_id and a.user_name='沙僧' ) c查看全部
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select sum(case when user_name=' 孙悟空' then kills end) as '孙悟空', sum(case when user_name='猪八戒' then kills end) as '猪八戒', sum(case when user_name='沙僧' then kills end) as '沙僧' from user1 a join use_kills b on a.id = b.user_id;查看全部
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使用序列化方法转换： select user_name, replace(substring(substring_index(mobile,','a.id),char_length(substring_index(mobile,',',a.id-1))+1),',','') as mobile --截取字符串 from tb_sequence as a cross join( select user_name, concat(mobile,',') as mobile, --在mobile结尾增加逗号 length(mobile)-length(replace(mobile,',',''))+1 as size --通过mobile总长度-排除逗号后的长度+1计算得出总段数 from user1 as b ) as b on a.id<=b.size查看全部
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使用union all连接转换： select user_name,'arms' as equipment, arms from user1 a join user1_equipment b on a.id=user_id union all select user_name,'clothing' as equipment, clothing from user1 a join user1_equipment b on a.id=user_id union all select user_name,'shoe' as equipment, shoe from user1 a join user1_equipment b on a.id=user_id查看全部
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1.判断数据是否重复： SELECT user_name , over, count(*) FROM user1_test GROUP BY user_name, over HAVING count(*)>1 2.删除重复数据，对于相同数据保留ID最大的 DELETE * FROM user1_test a JOIN( SELECT user_name,COUNT(*),MAX(id) AS id FROM user1_test GROUP BY user_name HAVING COUNT(*) > 1 ) b ON a.user_name = b.user_name WHERE a.id < b.id 3.将表中查询的数据再次插入到表中 INSERT INTO xmss_wh(XM_ID,WH_ID,YJ,SH,SHR,FJ_NAME,FJ_ID) SELECT XM_ID,WH_ID,YJ,SH,SHR,FJ_NAME,FJ_ID FROM xmss_wh WHERE ID=28; sql中的group by 用法解析： Group By语句从英文的字面意义上理解就是“根据(by)一定的规则进行分组(Group)”。 它的作用是通过一定的规则将一个数据集划分成若干个小的区域，然后针对若干个小区域进行数据处理。 --注意:group by 是先排序后分组； --举例子说明：如果要用到group by 一般用到的就是“每这个字” 例如说明现在有一个这样的表：每个部门有多少人 就要用到分组的技术 select DepartmentID as '部门名称', COUNT(*) as '个数' from BasicDepartment group by DepartmentID 这个就是使用了group by +字段进行了分组，其中我们就可以理解为我们按照了部门的名称ID DepartmentID将数据集进行了分组；然后再进行各个组的统计数据分别有多少； 如果不用count(*)等类似函数 select DepartmentID,DepartmentName from BasicDepartment group by DepartmentID 将会报错查看全部
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211·查看全部
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通过存储过程和事务等确保生成唯一序列号。可以通过创建一张表，记录某天的流水号最大是什么，然后通过某一个数可以叠加起来。 DECLARE v_cnt INT; DECLARE v_timestr INT; DECLARE rowcount BIGINT; SET v_timestr = DATE_FORMAT(NOW(),'%Y%m%d'); SELECT ROUND(RAND()*100,0)+1 INTO v_cnt; START TRANSACTION; UPDATE order_seq SET order_sn = order_sn + v_cnt WHERE timestr = v_timestr; IF ROW_COUNT() = 0 THEN INSERT INTO order_seq(timestr,order_sn) VALUES(v_timestr,v_cnt); END IF; SELECT CONCAT(v_timestr,LPAD(order_sn,7,0))AS order_sn FROM order_seq WHERE timestr = v_timestr; COMMIT;查看全部
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序列化方式进行行转列：<br> 1.首先我们先建立一个序列表<br> 2.思路：<br> 首先我们通过cross join 将user1_equipment 和 序列表 进行笛卡尔积，变成最终有多少条记录 c.id 必须小于等于user1_equipment的列数<br> 再通过case语句，分别取c.id=1,2,3...的对应的行的值，加上coalesce取不为空的数据<br> 最后加上对应的列名，<br> 示例如下：<br> SELECT user_name,<br> CASE WHEN c.id = 1 THEN 'arms'<br> WHEN c.id = 2 THEN 'clothing'<br> WHEN c.id = 3 THEN 'shoe'<br> END AS equipment,<br>//生成装备列 COALESCE(<br> CASE WHEN c.id = 1 THEN arms END<br> CASE WHEN c.id = 2 THEN clothing END<br> CASE WHEN c.id = 3 WHEN shoe END <br> ) AS eq_name<br>//coalesce取不为空的数据，那条不为空取那一条 FROM user1 a<br> JOIN user1_equipment b ON a.id=b.user_id<br> CROSS JOIN tb_sequence c WHERE c.id <= 3 ORDER BY user_name;查看全部
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实现如图的列转行的方法： 1.使用union all 将结果集 合并 select user_name,'arms' as equipment, arms from user1 a join user1_equipment b on a.id=user_id<br> union all<br> select user_name,'clothing' as equipment, clothing from user1 a join user1_equipment b on a.id=user_id;<br> union all<br> select user_name,'shoe' as equipment, shoe from user1 a join user1_equipment b on a.id=user_id;查看全部
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