#有点懒嘿嘿
L = [75, 92, 59, 68, 99]
sum=0
for ch in L:
sum+=ch
print(sum/(len(L)))
L = [75, 92, 59, 68, 99]
sum=0
for ch in L:
sum+=ch
print(sum/(len(L)))
2020-09-04
最赞回答 / 叁杯
for key, value in d.items()：输出的是key对应的value，而在这个dict中value就是三次成绩组成的list，而要求是输出每一次分数，所以需要再遍历一遍这个list 把每次的分数打印出来。
2020-09-03
L = [75, 92, 59, 68, 99]
i = 0
sum = 0
for x in L:
sum = x + sum
i = i + 1
ave = sum/i
print(ave)
这样更方便些
i = 0
sum = 0
for x in L:
sum = x + sum
i = i + 1
ave = sum/i
print(ave)
这样更方便些
2020-09-01
s1 = 'ABC'
s2 = '123'
s3 = 'xyz'
s = s1 + s2 + s3
for ch1 in s:
for ch2 in s:
for ch3 in s:
if ch1 != ch2 and ch1 != ch3 and ch2 != ch3:
print(ch1 + ch2 + ch3)
s2 = '123'
s3 = 'xyz'
s = s1 + s2 + s3
for ch1 in s:
for ch2 in s:
for ch3 in s:
if ch1 != ch2 and ch1 != ch3 and ch2 != ch3:
print(ch1 + ch2 + ch3)
2020-08-25
最新回答 / 禾希禾希
记录循环的次数，只要次数小于1，那么就return Nonedef func(param): x = 0 if isinstance(param,list): sum = 0 for item in param: if isinstance(item,int) or isinstance(item,float): ...
2020-08-24