已采纳回答 / 小颖April
因为有重合返回false，所以flag的值为假，not flag就为真，所以if not flag就是为了进入这个条件判断，接下来的操作就是打印重复元素了
2022-03-03
提供给大家参考
先把数据改成list，再改回tuple
# Enter a code
T = (1, 'CH', [3, 4])
print T
T = list(T)
print T
T[2] = tuple(T[2])
print T
T = tuple(T)
print T
先把数据改成list，再改回tuple
# Enter a code
T = (1, 'CH', [3, 4])
print T
T = list(T)
print T
T[2] = tuple(T[2])
print T
T = tuple(T)
print T
2022-03-03
最赞回答 / 金思录
答案里的item是随意定义的一个变量名，你可以把item换成A、B、c、d都可以。for item in L #将L中的每个元素依次赋予item这个变量，相当于第一次循环item=1，第二次循环item=2..... if item in S: #如果item的值在S中 S.remove(item) #那么就在S中移除item的值，那么在第一次循环中可以看到1确实在S中，所以在S中移除1 else: #如果item的值不在S中 S.add(item) #那...
2022-03-03
# Enter a code
students = ['Alice', 'Bob', 'Candy', 'David']
students[0] = 'Ellena'
print(students)
students.insert(1,'Alice')
print(students)
students.pop(2)
print(students)
students.append('Bob')
print(students)
students = ['Alice', 'Bob', 'Candy', 'David']
students[0] = 'Ellena'
print(students)
students.insert(1,'Alice')
print(students)
students.pop(2)
print(students)
students.append('Bob')
print(students)
2022-03-01
L=[95.5,85,59,66,72]
length=0;
i=0
j=0
for l in L:
length+=1
temp =0;
while i < length-1:
j = i+1
while j < length:
if L[i]<L[j]:
temp = L[i]
L[i] = L[j]
L[j] = temp
j+=1
i+=1
print(L[0],L[1],L[2])
length=0;
i=0
j=0
for l in L:
length+=1
temp =0;
while i < length-1:
j = i+1
while j < length:
if L[i]<L[j]:
temp = L[i]
L[i] = L[j]
L[j] = temp
j+=1
i+=1
print(L[0],L[1],L[2])
2022-02-27
s1='ABC'
s2='123'
s3='xyz'
for s11 in s1:
for s22 in s2:
for s33 in s3:
print(s11+s22+s33)
s2='123'
s3='xyz'
for s11 in s1:
for s22 in s2:
for s33 in s3:
print(s11+s22+s33)
2022-02-27
# coding: utf-8
s1 = '这是一句中英文混合的Python字符串：'
s2 = 'Hello World!'
print(s1+s2)
result = 's1{s2}'.format(s2='Hello World!')
print(result)
s1 = '这是一句中英文混合的Python字符串：'
s2 = 'Hello World!'
print(s1+s2)
result = 's1{s2}'.format(s2='Hello World!')
print(result)
2022-02-26
已采纳回答 / 幕布斯8123072
第一行：定义变量d为初始dict对象，即：d={}第二行：往d里面添加一个数据，结果为d={'Alice':[]}第三行：往d里面添加一个数据，结果为d={'Alice':[], 'Bob':[]}第四行：往d里面添加一个数据，结果为d={'Alice':[], 'Bob':[], 'Candy'=[]}
2022-02-25
num = 0
sum = 0
while True:
if num>1000:
break
sum = sum + num
num = num + 2
print(sum)
sum = 0
while True:
if num>1000:
break
sum = sum + num
num = num + 2
print(sum)
2022-02-25
num = 1
plus = 1
while num <= 20:
plus = plus * num
num = num + 1
print(plus)
plus = 1
while num <= 20:
plus = plus * num
num = num + 1
print(plus)
2022-02-25
L = [75, 92, 59, 68, 99, 100, 87, 71]
sum = 0.0
count = len(L)
for score in L:
sum = sum + score
ave = sum/count
print(sum,count)
print(ave)
sum = 0.0
count = len(L)
for score in L:
sum = sum + score
ave = sum/count
print(sum,count)
print(ave)
2022-02-25