# Enter a code
template='{} is short,{} need {}'
nei='Life'
nei2='you'
nei3='python'
result=template.format(nei,nei2,nei3)
print(result)
template='{} is short,{} need {}'
nei='Life'
nei2='you'
nei3='python'
result=template.format(nei,nei2,nei3)
print(result)
2021-08-24
# Enter a code
template='{2} is short,{0} need {1}'
nei='Life'
nei2='you'
nei3='python'
result=template.format(nei,nei2,nei3)
print(result)
template='{2} is short,{0} need {1}'
nei='Life'
nei2='you'
nei3='python'
result=template.format(nei,nei2,nei3)
print(result)
2021-08-24
最赞回答 / 巧克力可可块
个人觉得没什么区别上面的代码第一个L.pop(2)执行后L = ['Alice', 'Bob', 'David', 'Ellena'] ，第二个L.pop(2)执行后L = ['Alice', 'Bob', 'Ellena']下面的代码name=L.pop(3)执行后L = ['Alice', 'Bob', 'Candy', 'Ellena']，name=L.pop(2)执行后L = ['Alice', 'Bob', 'Ellena']（其实不用加name=就可以，name=是将值赋给name，只要有L....
2021-08-23
d = {
'Alice': 45,
'Bob': 60,
'Candy': 75,
'David': 86,
'Ellena': 49
}
name=('Alice','Bob', 'Candy', 'Mimi','David')
for i in name:
print(i+':'+str(d.get(i)))
'Alice': 45,
'Bob': 60,
'Candy': 75,
'David': 86,
'Ellena': 49
}
name=('Alice','Bob', 'Candy', 'Mimi','David')
for i in name:
print(i+':'+str(d.get(i)))
2021-08-22
最赞回答 / qq_慕桂英1478349
s1 = '一个长方形的长为3.14cm，宽为1.57cm，请计算这个长方形的面积，保留小数点后两位'num1=3.14num2=1.57s2=num1*num2s3=round(s2,2)print(s1)print(s3)
2021-08-21
s1='ABC'
s2='123'
s3='XYZ'
for a in s1:
for b in s2:
for c in s3:
for x in [a,b,c]:
for y in [a,b,c]:
for z in [a,b,c]:
if x!=y and x!=z and y!=z:
print(x+y+z)
s2='123'
s3='XYZ'
for a in s1:
for b in s2:
for c in s3:
for x in [a,b,c]:
for y in [a,b,c]:
for z in [a,b,c]:
if x!=y and x!=z and y!=z:
print(x+y+z)
2021-08-21
已采纳回答 / minzeOK
因为他先满足了，前面score>=80的条件，而用if elif else 只要满足一个条件就不会再走下面的判断了，你应该先判断score>=90后再判断score>=80
2021-08-20
# Enter a code
# -*- coding:utf-8 -*-
a = 'AABCDEFGHHIJ'
g = a[1:9]
print(g)
# -*- coding:utf-8 -*-
a = 'AABCDEFGHHIJ'
g = a[1:9]
print(g)
2021-08-20