def firstCharUpper(s):
return s[0].upper() + s[1:]
print firstCharUpper('hello')
print firstCharUpper('sunday')
print firstCharUpper('september')
return s[0].upper() + s[1:]
print firstCharUpper('hello')
print firstCharUpper('sunday')
print firstCharUpper('september')
2017-02-02
def firstCharUpper(s):
return s.title()
print firstCharUpper('hello')
print firstCharUpper('sunday')
print firstCharUpper('september')
这样算偷鸡吗-,-
return s.title()
print firstCharUpper('hello')
print firstCharUpper('sunday')
print firstCharUpper('september')
这样算偷鸡吗-,-
2017-02-02
可以用一种简单的算法,即将各个名字的小写形式也存入set集合中然后正常判断是in还是not in即可。
# -*- coding: utf-8 -*-
#
# File Desc : data structure set of python
# Author : wallace_lai
# At : 2017-02-02 22:03
s = set(['Adam', 'Lisa', 'Bart', 'Paul', 'adam', 'lisa', 'bart', 'paul'])
print 'adam' in s
print 'bart' in s
# -*- coding: utf-8 -*-
#
# File Desc : data structure set of python
# Author : wallace_lai
# At : 2017-02-02 22:03
s = set(['Adam', 'Lisa', 'Bart', 'Paul', 'adam', 'lisa', 'bart', 'paul'])
print 'adam' in s
print 'bart' in s
2017-02-02
一个比较简单的算法:
# -*- coding: utf-8 -*-
#
# File Desc : break statement in python
# Author : wallace_lai
# At : 2017-02-02 17:03
print pow(2, 20) - 1
# -*- coding: utf-8 -*-
#
# File Desc : break statement in python
# Author : wallace_lai
# At : 2017-02-02 17:03
print pow(2, 20) - 1
2017-02-02
print [int(str(m)+str(n)+str(m)) for m in range(1,10) for n in range(0,10)]
2017-02-02
d = { 'Adam': 95, 'Lisa': 85, 'Bart': 59, 'Paul': 74 }
print sum(d.values())*1.0/len(d)
print sum(d.values())*1.0/len(d)
2017-02-02
最新回答 / 慕粉4288469
可以用get,代码发上来看看加号不能拼接不同类型变量 在这道题中,print 'Adam:',d['Adam'] 前边是字符串,后边是数字 故不能使用加号
2017-02-01
sum = 0
n = 1
while True:
sum+=2**(n-1)
n+=1
if n>20:
break
print sum
这样应该可以吧
n = 1
while True:
sum+=2**(n-1)
n+=1
if n>20:
break
print sum
这样应该可以吧
2017-02-01