s = set(['Adam', 'Lisa', 'Bart', 'Paul'])
print s
print s
2017-01-09
d = {
'Adam': 95,
'Lisa': 85,
'Bart': 59
}
for n in d:
print str(n)+":"+str(d[n])
用逗号也行啊O__O "…
'Adam': 95,
'Lisa': 85,
'Bart': 59
}
for n in d:
print str(n)+":"+str(d[n])
用逗号也行啊O__O "…
2017-01-09
d = {
95: 'Adam',
85: 'Lisa',
59: 'Bart'
}
#d[72]='Paul'
#print d
d.update({80:'Bart'})
print d
95: 'Adam',
85: 'Lisa',
59: 'Bart'
}
#d[72]='Paul'
#print d
d.update({80:'Bart'})
print d
2017-01-09
print [m+n+x for m in range(100,1000) for n in range(100,1000) for x in range(100,1000) if m==x]
2017-01-09
已采纳回答 / 慕粉3996000
print (sum) 在while循环里,每一个sum的结果都会输出;而且不应该是sum+=sum+x,应该是sum+=x,或者sum=sum+x;x也错了
2017-01-09
s = set(['Adam', 'Lisa', 'Paul'])
L = ['Adam', 'Lisa', 'Bart', 'Paul']
for i in L:
if i in s:
s.remove(i)
else:
s.add(i)
print s
L = ['Adam', 'Lisa', 'Bart', 'Paul']
for i in L:
if i in s:
s.remove(i)
else:
s.add(i)
print s
2017-01-09
s = set([('Adam', 95), ('Lisa', 85), ('Bart', 59)])
for x in s:
print x[0],':',x[1]
for x in s:
print x[0],':',x[1]
2017-01-09
d = {
'Adam': 95,
'Lisa': 85,
'Bart': 59
}
for key in d:
print key+':'+str(d.get(key))
'Adam': 95,
'Lisa': 85,
'Bart': 59
}
for key in d:
print key+':'+str(d.get(key))
2017-01-09
d = {
95:'Adam',
85:'Lisa',
59:'Bart'
}
95:'Adam',
85:'Lisa',
59:'Bart'
}
2017-01-09
d = {
'Adam': 95,
'Lisa': 85,
'Bart': 59
}
print 'Adam:',d['Adam']
print 'Lisa:',d.get('Lisa')
print 'Bart:',d.get('Bart')
'Adam': 95,
'Lisa': 85,
'Bart': 59
}
print 'Adam:',d['Adam']
print 'Lisa:',d.get('Lisa')
print 'Bart:',d.get('Bart')
2017-01-09