d = { 'Adam': 95, 'Lisa': 85, 'Bart': 59, 'Paul': 74 }
sum = 0.0
for k, v in d.items():
sum = sum + v
print k,":",v
print 'average', ':', sum/len(d)
sum = 0.0
for k, v in d.items():
sum = sum + v
print k,":",v
print 'average', ':', sum/len(d)
2016-12-29
d = { 'Adam': 95, 'Lisa': 85, 'Bart': 59, 'Paul': 74 }
sum = 0.0
for i in d.itervalues():
sum=sum+i
print sum/len(d)
sum = 0.0
for i in d.itervalues():
sum=sum+i
print sum/len(d)
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a = 'Python'
print 'hello', a and 'world' #a是true,返回a
b = ''
print 'hello', b and 'world' #a是False 则返回b
print 'hello', a and 'world' #a是true,返回a
b = ''
print 'hello', b and 'world' #a是False 则返回b
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d = {
95: 'Adam',
85: 'Lisa',
59: 'Bart',
}
d[72] = 'pual'
我靠,这样了还。。。请检查代码中是否包含:d[ 72 ] = ' paul ',再试试!直接进入下一节
95: 'Adam',
85: 'Lisa',
59: 'Bart',
}
d[72] = 'pual'
我靠,这样了还。。。请检查代码中是否包含:d[ 72 ] = ' paul ',再试试!直接进入下一节
2016-12-29
def firstCharUpper(s):
return s[:1].upper()+s[1:]
print firstCharUpper('hello')
print firstCharUpper('sunday')
print firstCharUpper('september')
return s[:1].upper()+s[1:]
print firstCharUpper('hello')
print firstCharUpper('sunday')
print firstCharUpper('september')
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def square_of_sum(L):
sum=0
for i in L:
sum=sum+i**2
return sum
print square_of_sum([1, 2, 3, 4, 5])
print square_of_sum([-5, 0, 5, 15, 25])
sum=0
for i in L:
sum=sum+i**2
return sum
print square_of_sum([1, 2, 3, 4, 5])
print square_of_sum([-5, 0, 5, 15, 25])
2016-12-29
# 逻辑或 是 遇真则真 这里 变量 a的值 是 字符串 python 因此 直接返回 or 左边的值,ruguo如果左边的值 不为真 则继续 返回 右边的值
2016-12-29