print("\nfor计算平均成绩")
L3 = [75, 92, 59, 68]
sum0 = 0.0
for score in L3:
sum0 += score
size = len(L3)
print(size)
ava0 = sum0 / size
print(ava0)
L3 = [75, 92, 59, 68]
sum0 = 0.0
for score in L3:
sum0 += score
size = len(L3)
print(size)
ava0 = sum0 / size
print(ava0)
2016-12-08
L = [75, 92, 59, 68]
sum = 0.0
for score in L:
sum=score+sum
print sum / 4
sum = 0.0
for score in L:
sum=score+sum
print sum / 4
2016-12-08
d = { 'Adam': 95, 'Lisa': 85, 'Bart': 59, 'Paul': 74 }
L = d.values()
sum = 0.0
for x in L:
sum=sum+x
print sum/len(L)
L = d.values()
sum = 0.0
for x in L:
sum=sum+x
print sum/len(L)
2016-12-08
print '\n'.join(tds)
TypeError: sequence item 0: expected string, NoneType found
TypeError: sequence item 0: expected string, NoneType found
2016-12-07
s = set(['adam', 'lisa', 'bart', 'paul'])
print 'adam' in s
print 'bart' in s
我觉得根本不是 不是不识别小写 而是因为大写和小写不一样 那个set里面没小写 没有的东西肯定是false
这种写就能运行
print 'adam' in s
print 'bart' in s
我觉得根本不是 不是不识别小写 而是因为大写和小写不一样 那个set里面没小写 没有的东西肯定是false
这种写就能运行
2016-12-07
import math
def average(*args):
if len(args)==0:
return 0.0
else:
return sum(args)*1.0/len(args)
print average()
print average(1, 2)
print average(1, 2, 2, 3, 4)
def average(*args):
if len(args)==0:
return 0.0
else:
return sum(args)*1.0/len(args)
print average()
print average(1, 2)
print average(1, 2, 2, 3, 4)
2016-12-07
已采纳回答 / 7VincentGe
while True: x=x+1 y=x*x-2*x+1 sum=sum+y这一段表示的应该是0+1+4+9……的总和,也就是,0^2 + 1^2 + 2^2 + 3^2……的总和题目是2^0 + 2^1 + 2^2 + 2^3+……
2016-12-07