sum = 0
x =0
while True:
x = x + 1
if x > 100:
break
elif x%2!=0:
sum=sum+x
continue
print sum
sum=2500 就是过不了
x =0
while True:
x = x + 1
if x > 100:
break
elif x%2!=0:
sum=sum+x
continue
print sum
sum=2500 就是过不了
2016-12-03
s = set(['adam','Adam','bart','Bart'])
print 'adam' in s
print 'bart' in s
print 'adam' in s
print 'bart' in s
2016-12-03
d = {
'Adam': 95,
'Lisa': 85,
'Bart': 59
}
for key in d:
x = d.get(key)
print key,':',x
'Adam': 95,
'Lisa': 85,
'Bart': 59
}
for key in d:
x = d.get(key)
print key,':',x
2016-12-03
最赞回答 / 米老鼠的奋斗
sum = 0for x in range(1,100):while x<=100&x%2!=0: sum=sum+xprint sum这个是我的代码
2016-12-03
#已下为遍历 dict 的三种方法
#for (key, value) in d.items():
# print("%s: %s" % (key, value))
#
#print 'Adam:' + str(d.get('Adam'))
#print 'Lisa:'+str(d.get('Lisa'))
#print 'Bart:'+str(d.get('Bart'))
#
#print 'Adam:',d.get('Adam')
#print 'Lisa:',d.get('Lisa')
#print 'Bart:',d.get('Bart')
#for (key, value) in d.items():
# print("%s: %s" % (key, value))
#
#print 'Adam:' + str(d.get('Adam'))
#print 'Lisa:'+str(d.get('Lisa'))
#print 'Bart:'+str(d.get('Bart'))
#
#print 'Adam:',d.get('Adam')
#print 'Lisa:',d.get('Lisa')
#print 'Bart:',d.get('Bart')
2016-12-03
告诉大家一个很屌的方法,那就是使用原始输入方法,使用r'xxxx' (其中xxx就是要打印的字符串)
s =r' Python was started in 1989 by "Guido" ' #使用r''把字符串当作原始数据,赋值给s
print s #打印s
s =r' Python was started in 1989 by "Guido" ' #使用r''把字符串当作原始数据,赋值给s
print s #打印s
2016-12-03
我还能说什么呢,我也以为最后一个要输出L[0]或者L[1],结果是-4,不是只有三个成绩么- - 昨晚上一个再来做这一个 简直怀疑人生啊
2016-12-03
x1 = 1
d = 3
n = 100
x100 = x1+(n-1)*d
s = (x1+x100)*n/2
print s
d = 3
n = 100
x100 = x1+(n-1)*d
s = (x1+x100)*n/2
print s
2016-12-03
s = set([('Adam', 95), ('Lisa', 85), ('Bart', 59)])
for x in s:
print x[0],':',x[1]
for x in s:
print x[0],':',x[1]
2016-12-03
d = {
'Adam': 95,
'Lisa': 85,
'Bart': 59
}
for key in d:
print key,':',d[key]
'Adam': 95,
'Lisa': 85,
'Bart': 59
}
for key in d:
print key,':',d[key]
2016-12-03
for x in [1,2,3,4,5,6,7,8,9 ]:
for y in [ 1,2,3,4,5,6,7,8,9 ]:
if x<y:
print x*10+y
for y in [ 1,2,3,4,5,6,7,8,9 ]:
if x<y:
print x*10+y
2016-12-03