写复杂了
def change_int(y):
inr = []
for value in y:
inr.append(int(value))
return inr
num = [str(i)+str(j)+str(i) for i in range(1,10) for j in range(10)]
new_num = change_int(num)
print new_num
def change_int(y):
inr = []
for value in y:
inr.append(int(value))
return inr
num = [str(i)+str(j)+str(i) for i in range(1,10) for j in range(10)]
new_num = change_int(num)
print new_num
2016-11-29
L = ['Adam', 'Lisa', 'Paul', 'Bart']
L.pop(2)
L.pop(2)
print L
L.pop(2)
L.pop(2)
print L
2016-11-29
d = { 'Adam': 95, 'Lisa': 85, 'Bart': 59, 'Paul': 74 }
print float(sum(d.values())) / len(d)
d = { 'Adam': 95, 'Lisa': 85, 'Bart': 59, 'Paul': 74 }
sum = 0.0
for value in d.values():
sum += value
print sum / len(d)
print float(sum(d.values())) / len(d)
d = { 'Adam': 95, 'Lisa': 85, 'Bart': 59, 'Paul': 74 }
sum = 0.0
for value in d.values():
sum += value
print sum / len(d)
2016-11-29
最新回答 / 慕粉1504449410
L.sort() #排序print L[-3] #按照倒序索引打印出倒数第一print L[-2] #按照倒序索引打印出倒数第二print L[-1] #按照倒序索引打印出倒数第三
2016-11-29
d = {
'Adam': 95,
'Lisa': 85,
'Bart': 59
}
for key in d:
print key,':',d.get(key)
'Adam': 95,
'Lisa': 85,
'Bart': 59
}
for key in d:
print key,':',d.get(key)
2016-11-29