s = set(['Adam', 'Lisa', 'Paul'])
L = ['Adam', 'Lisa', 'Bart', 'Paul']
for i in L:
if i in s:
s.remove(i)
else:
s.add(i)
print s
L = ['Adam', 'Lisa', 'Bart', 'Paul']
for i in L:
if i in s:
s.remove(i)
else:
s.add(i)
print s
2016-11-26
# -*- coding: utf-8 -*-
d = {
95:'Adam',
85:'Lisa',
59:'Bart',
}
print str(95) + ':' + d[95]
我不想吐槽这个判定了
d = {
95:'Adam',
85:'Lisa',
59:'Bart',
}
print str(95) + ':' + d[95]
我不想吐槽这个判定了
2016-11-26
我用的是python3.5版本,发现有两点可以与大家分享:1、python3.5版本输入中文字符串的时候,可以不用输入“U”;2、此版本也不用输入“#-*-coding:utf-8 -*-”。
2016-11-26
sum = 0
x = 0
while True:
x = x + 1
if x > 100:
break
if x%2 is not 0:
sum = sum + x
continue
print sum
x = 0
while True:
x = x + 1
if x > 100:
break
if x%2 is not 0:
sum = sum + x
continue
print sum
2016-11-26
sum = 0
x = 1
n = 1
while True:
sum = sum + 2**(n-x)
n += 1
if n > 20:
break
print sum
x = 1
n = 1
while True:
sum = sum + 2**(n-x)
n += 1
if n > 20:
break
print sum
2016-11-26
我想不通你们还要用循环?
x1 = 1
d = 3
n = 100
x100 = x1 + d*(n - 1)
s = ((x1 + x100)*n)/2
print s
x1 = 1
d = 3
n = 100
x100 = x1 + d*(n - 1)
s = ((x1 + x100)*n)/2
print s
2016-11-26