print (45678+0x12fd2)
print ("learn python in imooc")
print (100<99)
print (0xff==255)
print ("learn python in imooc")
print (100<99)
print (0xff==255)
2016-11-16
d = {
'Adam': 95,
'Lisa': 85,
'Bart': 59
}
for key in d:
print key + ':', str(d[key])
'Adam': 95,
'Lisa': 85,
'Bart': 59
}
for key in d:
print key + ':', str(d[key])
2016-11-16
d = { 'Adam': 95, 'Lisa': 85, 'Bart': 59, 'Paul': 74 }
sum = 0.0
for k, v in d.items():
sum = sum + v
print k, ":", v
average = sum/(len(d)+0.0)
print 'average', ':', average
sum = 0.0
for k, v in d.items():
sum = sum + v
print k, ":", v
average = sum/(len(d)+0.0)
print 'average', ':', average
2016-11-16
已采纳回答 / 浪子彦青
list只有3个分数,索引的时候只能索引三项。使用L[0],L[1],L[2]即可,当使用L[3]索引的时候,list里不存在第四个分数,会报错,告诉你这个L[3]的索引超过范围,是有问题的,需要你去修改,你可以自己使用cmd进行编译,参考下图 (ps*采纳为最佳答案吧)<...图片...>
2016-11-16
d = { 'Adam': 95, 'Lisa': 85, 'Bart': 59, 'Paul': 74 }
average = 0.0
s = []
for x in d.values():
s.append(x)
average = (sum(s)+0.0)/len(s)
print average
average = 0.0
s = []
for x in d.values():
s.append(x)
average = (sum(s)+0.0)/len(s)
print average
2016-11-16
x1 = 1
d = 3
n = 100
x100 = 0
t=1
while (t <= n):
x100 = x100 + x1
x1 = x1 + d
t = t + 1
s = x100
print s
d = 3
n = 100
x100 = 0
t=1
while (t <= n):
x100 = x100 + x1
x1 = x1 + d
t = t + 1
s = x100
print s
2016-11-16