最新回答 / EdwardWin
不需要加u'...' 。因为 # -*- coding: utf-8 -*- 代表的是utf-8的编码,其实在终端中并不会冲突,只是显得多余罢了。print r'''想要打印的中文''' or print u'''想要打印的中文''' 上节的r'''...''',可以不需要输入\转义。如果想要换行的话直接回车换行即可。print r'''你好加油!'''
2016-10-30
sum = 0
x = 0
while True:
x = x + 1
if x > 100:
break
if x%2==0:
continue
sum+=x
print sum
x = 0
while True:
x = x + 1
if x > 100:
break
if x%2==0:
continue
sum+=x
print sum
2016-10-30
sum = 0
x = 1
n = 1
while True:
sum+=x
x+=x
n+=1
if n>20:
break
print sum
x = 1
n = 1
while True:
sum+=x
x+=x
n+=1
if n>20:
break
print sum
2016-10-30
sum = 0
x = 1
while x<100:
sum+=x
x+=1
print sum
while循环的两句没有括号,表示难以理解
x = 1
while x<100:
sum+=x
x+=1
print sum
while循环的两句没有括号,表示难以理解
2016-10-30
L = [75, 92, 59, 68]
sum = 0.0
for num in L:
sum+=num
print sum / 4
普通的累加
sum = 0.0
for num in L:
sum+=num
print sum / 4
普通的累加
2016-10-30
L = ['Adam', 'Lisa', 'Bart']
M=L[0]
L[0]=L[2]
L[2]=M
print L
简单的交换顺序
M=L[0]
L[0]=L[2]
L[2]=M
print L
简单的交换顺序
2016-10-30
# -*- coding: utf-8 -*-
print '''静夜思
床前明月光,
疑是地上霜。
举头望明月,
低头思故乡。'''
print '''静夜思
床前明月光,
疑是地上霜。
举头望明月,
低头思故乡。'''
2016-10-30
x1 = 1
d = 3
n = 100
x100 = 3*(100-1)+1
s = (x1+x100)*100/2
print s
d = 3
n = 100
x100 = 3*(100-1)+1
s = (x1+x100)*100/2
print s
2016-10-30
x1 = 1
d = 3
n = 100
x100 = 3*(100-1)+1
s = (x1+x100)*100/2
print s
d = 3
n = 100
x100 = 3*(100-1)+1
s = (x1+x100)*100/2
print s
2016-10-30
print 'helllo,python'
print 'hello',',python'
print 'hello',',python'
2016-10-30
print 45678+0x12fd2
print 'Learn Python In imooc'
print 100<99
print 0xff==255
print 'Learn Python In imooc'
print 100<99
print 0xff==255
2016-10-30