def square_of_sum(L):
new=[x*x for x in L]
return sum(new)
print square_of_sum([1, 2, 3, 4, 5])
print square_of_sum([-5, 0, 5, 15, 25])
new=[x*x for x in L]
return sum(new)
print square_of_sum([1, 2, 3, 4, 5])
print square_of_sum([-5, 0, 5, 15, 25])
2016-07-07
for x in ['1','2','3','4','5','6','7','8','9']:
for y in ['0','1','2','3','4','5','6','7','8','9']:
if x<y:
print(x+y+"("+x+"<"+y+")"+"\n")
for y in ['0','1','2','3','4','5','6','7','8','9']:
if x<y:
print(x+y+"("+x+"<"+y+")"+"\n")
2016-07-07
s = set(['Adam', 'Lisa', 'Paul'])
L = ['Adam', 'Lisa', 'Bart', 'Paul']
for name in L:
if name in s:
s.remove(name)
else:
s.add(name)
print s
L = ['Adam', 'Lisa', 'Bart', 'Paul']
for name in L:
if name in s:
s.remove(name)
else:
s.add(name)
print s
2016-07-07
s = set([('Adam', 95), ('Lisa', 85), ('Bart', 59)])
for x in s:
print str(x[0])+':'+str(x[1])
for x in s:
print str(x[0])+':'+str(x[1])
2016-07-07
s=set(['adam','Lisa','bart','Paul'])
print 'adam' in s
print 'bart' in s
print 'adam' in s
print 'bart' in s
2016-07-07
d = {
'Adam': 95,
'Lisa': 85,
'Bart': 59
}
for key in d:
print key
print ':'+str(d[key])
'Adam': 95,
'Lisa': 85,
'Bart': 59
}
for key in d:
print key
print ':'+str(d[key])
2016-07-07
s = set([('Adam', 95), ('Lisa', 85), ('Bart', 59)])
for x in s:
print x[0],':',x[1]
for x in s:
print x[0],':',x[1]
2016-07-07
已采纳回答 / Dai9210
取数间隔。三个参数分别是第一个数位置，最后一个数位置，取数间隔。例如习题中：L = range(1, 101)print L[-46: :5]L是1-100一共100个数字，索引分别为0-99，L[-46: :5]从倒数第46个开始取数（即55），到最后，取数规则是每隔5个数取一次，因此输出结果为[55,60,65,70,75,80,85,90,95,100]
2016-07-07
已采纳回答 / 慕粉3602626
0x表示16进制数，后面的1,2，f，d，2，依次对应10进制的1, 2，15，13，2；所以0x12fd2（16进制）= 1*16^4 + 2*16^3 + 15*16^2 + 13*16 + 2 = 77778
2016-07-06
sum = 0
x = 0
while True:
x = x + 1
if x > 100:
break
if x%2 == 0:
continue
sum = sum + x
print sum
x = 0
while True:
x = x + 1
if x > 100:
break
if x%2 == 0:
continue
sum = sum + x
print sum
2016-07-06