已采纳回答 / qq_爱的前奏哼哼_0
以我所学,list不能直接用你说的这种形式表达,得一个个列出来,如:for i in [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15]:你所说的形式是对list进行操作的“切片截取”,所以还是得学会使用range来构造连续数字,之后再用切片进行处理。
2016-06-01
如果中文字符串在Python环境下遇到 UnicodeDecodeError,这是因为.py文件保存的格式有问题。可以在第一行添加注释
# -*- coding: utf-8 -*-
目的是告诉Python解释器,用UTF-8编码读取源代码。然后用Notepad++ 另存为... 并选择UTF-8格式保存。
# -*- coding: utf-8 -*-
目的是告诉Python解释器,用UTF-8编码读取源代码。然后用Notepad++ 另存为... 并选择UTF-8格式保存。
2016-05-31
d = {
'Adam': 95,
'Lisa': 85,
'Bart': 59
}
for key in d:
print key+":"+str(d.get(key));
'Adam': 95,
'Lisa': 85,
'Bart': 59
}
for key in d:
print key+":"+str(d.get(key));
2016-05-31
Python2.7.11 Pycharm5 验证以下代码通过
L = [95.5, 85, 59]
print L[-1]
print L[-2]
print L[-3]
print L[0]
以下答案代码报错
L = [95.5, 85, 59]
print L[-1]
print L[-2]
print L[-3]
print L[-4]
L = [95.5, 85, 59]
print L[-1]
print L[-2]
print L[-3]
print L[0]
以下答案代码报错
L = [95.5, 85, 59]
print L[-1]
print L[-2]
print L[-3]
print L[-4]
2016-05-31
sum = 0
x = 1
n = 1
while True:
print x
sum=sum+x
x=x*2;
n=n+1
if(n>20):
break
print sum
x = 1
n = 1
while True:
print x
sum=sum+x
x=x*2;
n=n+1
if(n>20):
break
print sum
2016-05-31
sum = 0
x = 1
n = 1
while True:
sum=sum+x
x=2^(n-1)
n=n+1
if n>20:
break
print sum
x = 1
n = 1
while True:
sum=sum+x
x=2^(n-1)
n=n+1
if n>20:
break
print sum
2016-05-31
我是小白,我为自己鼓掌,耶
print [101 * m +10 * n for m in range(1 , 10) for n in range(0, 10)]
print [101 * m +10 * n for m in range(1 , 10) for n in range(0, 10)]
2016-05-31