L = []
for x in range(1,101):
L.append(x*x)
print sum(L)
for x in range(1,101):
L.append(x*x)
print sum(L)
2016-05-26
sum = 0
x = 0
while True:
x = x + 1
if not (x%2):
continue
if x > 100:
break
sum += x;
print sum
x = 0
while True:
x = x + 1
if not (x%2):
continue
if x > 100:
break
sum += x;
print sum
2016-05-26
for x in [1, 2, 3, 4, 5, 6, 7, 8]:
for y in range(x + 1, 10):
z = str(x) + str(y)
z = int(z)
print z
for y in range(x + 1, 10):
z = str(x) + str(y)
z = int(z)
print z
2016-05-25
for x in [1, 2, 3, 4, 5, 6, 7, 8]:
for y in range(x + 1, 10):
if x < y:
z = str(x) + str(y)
z = int(z)
print z
for y in range(x + 1, 10):
if x < y:
z = str(x) + str(y)
z = int(z)
print z
2016-05-25
for x in [1, 2, 3, 4, 5, 6, 7, 8, 9]:
for y in [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]:
if x < y:
z = str(x) + str(y)
z = int(z)
print z
for y in [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]:
if x < y:
z = str(x) + str(y)
z = int(z)
print z
2016-05-25
sum = 0
x = 0
while True:
x = x + 1
if x > 100:
break
if x % 2 == 0:
continue
sum += x
print sum
x = 0
while True:
x = x + 1
if x > 100:
break
if x % 2 == 0:
continue
sum += x
print sum
2016-05-25
已采纳回答 / ALEX丶
如果把break写在最后的话,你的循环当中要n>20才能才能执行中间的代码,由于x=1,而x=x*2无法执行,所以循环永远无法停止,必须把break写在x=x*2之前
2016-05-25