sum = 0.0
for score in d.itervalues():
sum += score
print sum / len(d)
for score in d.itervalues():
sum += score
print sum / len(d)
2016-04-23
L = [75, 92, 59, 68]
sum = 0.0
for score in L:
sum = sum + score
print sum / 4
sum = 0.0
for score in L:
sum = sum + score
print sum / 4
2016-04-23
L = range(1, 101)
print L[0:10]
print L[2:100:3]
print L[4:50:5]
print L[0:10]
print L[2:100:3]
print L[4:50:5]
2016-04-23
def average(*args):
sum = 0.0
if len(args) == 0:
return 0.0
else:
for i in args:
sum += i
aver = sum / len(args)
return aver
print average()
print average(1, 2)
print average(1, 2, 2, 3, 4)
sum = 0.0
if len(args) == 0:
return 0.0
else:
for i in args:
sum += i
aver = sum / len(args)
return aver
print average()
print average(1, 2)
print average(1, 2, 2, 3, 4)
2016-04-23
def greet(s = 'world'):
print 'Hello,',s,'.'
greet()
greet('Bart')
print 'Hello,',s,'.'
greet()
greet('Bart')
2016-04-23
def move(n, a, b, c):
if n == 1:
print a, '-->',c
else:
move(n-1, a, c, b)
move(1, a, b, c)
move(n-1, b, a, c)
move(4, 'A', 'B', 'C')
if n == 1:
print a, '-->',c
else:
move(n-1, a, c, b)
move(1, a, b, c)
move(n-1, b, a, c)
move(4, 'A', 'B', 'C')
2016-04-23
import math
def quadratic_equation(a, b, c):
d = b*b - 4*a*c
if d >= 0:
x1 = (-b + math.sqrt(d))/(2*a)
x2 = (-b - math.sqrt(d))/(2*a)
return x1,x2
else:
x1 = (-b + i * math.sqrt(-d))/(2*a)
x2 = (-b - i * math.sqrt(-d))/(2*a)
return x1,x2
def quadratic_equation(a, b, c):
d = b*b - 4*a*c
if d >= 0:
x1 = (-b + math.sqrt(d))/(2*a)
x2 = (-b - math.sqrt(d))/(2*a)
return x1,x2
else:
x1 = (-b + i * math.sqrt(-d))/(2*a)
x2 = (-b - i * math.sqrt(-d))/(2*a)
return x1,x2
2016-04-23
import math
def quadratic_equation(a, b, c):
d = b*b - 4*a*c
if d >= 0:
x1 = (-b + math.sqrt(d))/(2*a)
x2 = (-b - math.sqrt(d))/(2*a)
return x1,x2
else:
x1 = (-b + i * math.sqrt(d))/(2*a)
x2 = (-b - i * math.sqrt(d))/(2*a)
return x1,x2
def quadratic_equation(a, b, c):
d = b*b - 4*a*c
if d >= 0:
x1 = (-b + math.sqrt(d))/(2*a)
x2 = (-b - math.sqrt(d))/(2*a)
return x1,x2
else:
x1 = (-b + i * math.sqrt(d))/(2*a)
x2 = (-b - i * math.sqrt(d))/(2*a)
return x1,x2
2016-04-23