#input code
print 'hello,python'
print ('hello','world')
print 'hello,python'
print ('hello','world')
2016-03-23
print 45678 + 0x12fd2
print 'Learn Python in imooc'
print 100<99
print 0xff == 255
print 'Learn Python in imooc'
print 100<99
print 0xff == 255
2016-03-23
import math
def quadratic_equation(a, b, c):
return (-b+math.sqrt(b*b-4.0*a*c))/(2*a),(-b-math.sqrt(b*b-4.0*a*c))/(2*a)
print quadratic_equation(2, 3, 0)
print quadratic_equation(1, -6, 5)
def quadratic_equation(a, b, c):
return (-b+math.sqrt(b*b-4.0*a*c))/(2*a),(-b-math.sqrt(b*b-4.0*a*c))/(2*a)
print quadratic_equation(2, 3, 0)
print quadratic_equation(1, -6, 5)
2016-03-23
修改;age =20
if age >= 18:
print 'adult'
elif age >= 6:
print 'teenager'
else:
print 'kid'
if age >= 18:
print 'adult'
elif age >= 6:
print 'teenager'
else:
print 'kid'
2016-03-23
也就是说 TUPLE 的所指示的是不能变的, 里面有三个元素 期中一个是LIST。 而题目是让我们 不让内容 AB发生改变。
2016-03-23
d = {
'Adam': 95,
'Lisa': 85,
'Bart': 59,
}
d.insert('Paul': 75)
最后一个 key: value 的逗号可以省略。但省略后,此题insert通不过。
'Adam': 95,
'Lisa': 85,
'Bart': 59,
}
d.insert('Paul': 75)
最后一个 key: value 的逗号可以省略。但省略后,此题insert通不过。
2016-03-23
d = { 'Adam': 95, 'Lisa': 85, 'Bart': 59 }
def generate_tr(name, score):
return '<tr><td>%s</td><td>%s</td></tr>' % (name, score)
tds = ['<tr><td>%s</td><td>%s</td></tr><td style="color:red"> ' for name, score in d.iteritems()]
def generate_tr(name, score):
return '<tr><td>%s</td><td>%s</td></tr>' % (name, score)
tds = ['<tr><td>%s</td><td>%s</td></tr><td style="color:red"> ' for name, score in d.iteritems()]
2016-03-23
d = { 'Adam': 95, 'Lisa': 85, 'Bart': 59, 'Paul': 74 }
sum = 0.0
for v in d.itervalues():
sum=sum+v
average=sum/len(d)
print average
sum = 0.0
for v in d.itervalues():
sum=sum+v
average=sum/len(d)
print average
2016-03-23
d = { 'Adam': 95, 'Lisa': 85, 'Bart': 59, 'Paul': 74 }
sum = 0.0
for v in d.itervalues():
sum=sum+v
average=sum/4
print average
sum = 0.0
for v in d.itervalues():
sum=sum+v
average=sum/4
print average
2016-03-23
def firstCharUpper(s):
a=s[:1].upper()
b=s[1:]
s=a+b
return s
print firstCharUpper('hello')
print firstCharUpper('sunday')
print firstCharUpper('september')
a=s[:1].upper()
b=s[1:]
s=a+b
return s
print firstCharUpper('hello')
print firstCharUpper('sunday')
print firstCharUpper('september')
2016-03-23