x1 = 1
d = 3
n = 100
x100 =x1+(n-1)*d
s =n*(x1+x100)/2
print s
s=14950
d = 3
n = 100
x100 =x1+(n-1)*d
s =n*(x1+x100)/2
print s
s=14950
2016-03-20
# encoding: utf-8
import math
def quadratic_equation(a, b, c):
dert = b*b - 4*a*c
if dert < 0:
print '此方程没有实数解。'
else:
x1 = (-b + math.sqrt(dert))/(2*a)
x2 = (-b - math.sqrt(dert))/(2*a)
return x1,x2
import math
def quadratic_equation(a, b, c):
dert = b*b - 4*a*c
if dert < 0:
print '此方程没有实数解。'
else:
x1 = (-b + math.sqrt(dert))/(2*a)
x2 = (-b - math.sqrt(dert))/(2*a)
return x1,x2
2016-03-20
def square_of_sum(L):
sum = 0
for number in L:
sum = sum + number*number
return sum
print square_of_sum([1, 2, 3, 4, 5])
print square_of_sum([-5, 0, 5, 15, 25])
sum = 0
for number in L:
sum = sum + number*number
return sum
print square_of_sum([1, 2, 3, 4, 5])
print square_of_sum([-5, 0, 5, 15, 25])
2016-03-20
已采纳回答 / 叶重楼
不大明白你的意思。你是说在交互环境ILDE中写出多行print而不运行吗?那不行的,本来就是写一行就运行一行。如果你要这么做,就得在编辑器比如笔记本里写好,然后存为.py文件,再运行它。
2016-03-19
这样写,竟然通过了
L = [95.5, 85, 59]
print L[-1]
print L[-2]
print L[-3]
print L[-4]
L = [95.5, 85, 59]
print L[-1]
print L[-2]
print L[-3]
print L[-4]
2016-03-19
最新回答 / weiTheroadnot_0
print [i*100+j*10+k for i in range(1,10) for j in range(0,10) for k in range(0,10) if i==k ]
2016-03-19