print 45678+0x12fd2
print 'learn python in imooc'
print 100<99
print 0xff==255
print 'learn python in imooc'
print 100<99
print 0xff==255
2016-02-17
已采纳回答 / qq_梦星墓痕_0
s = set(['Adam', 'Lisa', 'Bart', 'Paul'])#print 'adam'.capitalize() in s#print 'bart'.capitalize() in sfor x in s: if 'adam'.lower()==x.lower(): print 'True' else: continue没有更简洁的,这样可以忽略大小写，凑乎用吧
2016-02-17
sum = 0
x = 0
while True:
x+=1
if x <= 100:
if x%2 == 1:
sum+=x
else:continue
else:break
print sum
x = 0
while True:
x+=1
if x <= 100:
if x%2 == 1:
sum+=x
else:continue
else:break
print sum
2016-02-17
sum = 0
x = 1
while sum < 100:
while x%2==1:
sum+=x
x+=1
print sum
pycharm无反应了，这里通过了。。
x = 1
while sum < 100:
while x%2==1:
sum+=x
x+=1
print sum
pycharm无反应了，这里通过了。。
2016-02-17
已采纳回答 / GeorgeHao
循环到n=21的时候，先执行sum=sum+x；然后x=x*2,再执行break循环这样实际上sum算的是前21项之和。所以：将if判断放到while行下面就可以了。
2016-02-16
