我想复杂了……
t = ('a', 'b', [('A',), ('B',)])
t = ('a', 'b', [('A',), ('B',)])
2016-01-13
s = set(['Adam', 'Lisa', 'Paul'])
L = ['Adam', 'Lisa', 'Bart', 'Paul']
for x in L:
if x in s:
s.remove(x)
else:
s.add(x)
print s
L = ['Adam', 'Lisa', 'Bart', 'Paul']
for x in L:
if x in s:
s.remove(x)
else:
s.add(x)
print s
2016-01-12
d = {
'Adam': 95,
'Lisa': 85,
'Bart': 59
}
for name in d:
print name+':',d[name]
'Adam': 95,
'Lisa': 85,
'Bart': 59
}
for name in d:
print name+':',d[name]
2016-01-12
因为当age = 20时,满足代码if age >= 6:
print 'teenager'
所以执行完对应的代码块,后面的条件判断就直接忽略,未执行age >= 18的判断,所以结果不是adult
print 'teenager'
所以执行完对应的代码块,后面的条件判断就直接忽略,未执行age >= 18的判断,所以结果不是adult
2016-01-12
L = ['Adam', 'Lisa', 'Bart']
p=L[2]
L[2]=L[0]
L[0]=p
print L
p=L[2]
L[2]=L[0]
L[0]=p
print L
2016-01-12
for x in ['1','2','3','4','5','6','7','8','9' ]:
for y in [ '0','1','2','3','4','5','6','7','8','9' ]:
if x < y:
print x+y
for y in [ '0','1','2','3','4','5','6','7','8','9' ]:
if x < y:
print x+y
2016-01-12