s = set([('Adam', 95), ('Lisa', 85), ('Bart', 59)])
for x in s:
print x[0],":",x[1] x[0],对应列表里的第一个元素
x[1],对应列表里的第二个元素
for x in s:
print x[0],":",x[1] x[0],对应列表里的第一个元素
x[1],对应列表里的第二个元素
2015-12-22
tuple复习 tuple是一个无法改变的'list'
tuple有序 使用其中元素就是 tuple名字[序列] 此处名字x
tuple有序 使用其中元素就是 tuple名字[序列] 此处名字x
2015-12-22
L = ['Adam', 'Lisa', 'Bart']
L[2], L[0] = L[0], L[2]
print L
L[2], L[0] = L[0], L[2]
print L
2015-12-22
最赞回答 / 有心寻性
和等差数列差不多,从1开始写出3的倍数,数到10的时候会数出3个[3,6,9]数到11的时候也是三个[3,6,9]计算结果一样你写的这两个range函数用哪个都可以range(a,b,c)a代表开始(包含)b代表结束(不包含)c代表步长(类似于等差数列的公差值)
2015-12-22
for x in [ 1,2,3,4,5,6,7,8,9 ]:
for y in [ 0,1,2,3,4,5,6,7,8,9 ]:
if x<y:
print x*10+y
for i in range(1,10,1):
for j in range(0,10):
if i<j:
print str(i)+str(j)
for y in [ 0,1,2,3,4,5,6,7,8,9 ]:
if x<y:
print x*10+y
for i in range(1,10,1):
for j in range(0,10):
if i<j:
print str(i)+str(j)
2015-12-21
for x in [ 1,2,3,4,5,6,7,8,9 ]:
for y in [ 0,1,2,3,4,5,6,7,8,9 ]:
if x<y:
print x*10+y
for y in [ 0,1,2,3,4,5,6,7,8,9 ]:
if x<y:
print x*10+y
2015-12-21
sum = 0
x = 0
while True:
x = x + 1
if x > 100:
break
if x%2==0:
continue
sum+=x
print sum
x = 0
while True:
x = x + 1
if x > 100:
break
if x%2==0:
continue
sum+=x
print sum
2015-12-21
sum = 0
x = 1
n = 1
while True:
sum+=x
x*=2
n+=1
if n>20:
break
print sum
x = 1
n = 1
while True:
sum+=x
x*=2
n+=1
if n>20:
break
print sum
2015-12-21