#Enter a code
print 45678+0x12fd2
print "Learn Python in imooc"
print 100<99
print 0xff==255
print 45678+0x12fd2
print "Learn Python in imooc"
print 100<99
print 0xff==255
2015-10-16
讲师回答 / PengCheng
如果人数不止3个人的话,例如L = ['Adam', 'Lisa', 'Bart','haha']L.insert(-1, 'Paul')print L这样的,你输出就是 ['Adam', 'Lisa', 'Bart','Paul','haha'] 了。看实际运用吧。
2015-10-15
s = set(['Adam', 'Lisa', 'Paul'])
L = ['Adam', 'Lisa', 'Bart', 'Paul']
for i in L:
if i in s:
s.remove(i)
else:
s.add(i)
print s
L = ['Adam', 'Lisa', 'Bart', 'Paul']
for i in L:
if i in s:
s.remove(i)
else:
s.add(i)
print s
2015-10-15
print r'''"To be ,or not to be":
that is the question.
Whether it's nobler in the mind to suffer.'''
不明白到底哪里错了
that is the question.
Whether it's nobler in the mind to suffer.'''
不明白到底哪里错了
2015-10-15
好像还可以用于求和啊!
L=list(range(100))
s=0.0
for x in L:
s=s+x
print(s)
L=list(range(100))
s=0.0
for x in L:
s=s+x
print(s)
2015-10-14
单元素 tuple 要多加一个逗号“,” >>> t = (1,)
多元素 tuple 加不加这个额外的“,” >>> t = (1,2,3)
多元素 tuple 加不加这个额外的“,” >>> t = (1,2,3)
2015-10-14
print [100*a + 10*b + c for a in range(1, 10) for b in range(0, 10) for c in range(0,10) if a == c]
2015-10-14
L = [95.5, 85, 59,59]
print L[-1]
print L[-2]
print L[-3]
print L[-4]
这样就能过
print L[-1]
print L[-2]
print L[-3]
print L[-4]
这样就能过
2015-10-14