python进阶_技术问答

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python进阶

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解朝雨

def is_sqr(x):
return (x**0.5) % 1 == 0

print filter(is_sqr, range(1, 101))

0 2-6 python中filter()函数

2019-11-30

慕侠7424073

# -*- coding: utf-8 -*-

def count():
fs = []
for i in range(1, 4):
def f(j):
def g():
return j*j
return g

fs.append(f(i))
return fs

f1, f2, f3= count()

print(f1(), f2(), f3())

print(count())

0 2-9 python中闭包

2019-11-28

慕侠7424073

# -*- coding: utf-8 -*-
from functools import reduce
def calc_prod(lst):
def prod(x, y):
return x*y
return reduce(prod, lst)

f = calc_prod([1, 2, 3, 4])
print(f)

0 2-8 python中返回函数

2019-11-28

慕仙4481627

毫无用处！

1 4-7 python中类属性和实例属性名字冲突怎么办

2019-11-27

hen_nam

只有父类和子类都定义了 __slots__ 属性，子类的属性限制才有效
子类的属性限制等于父类的 __slots__ 属性加子类的 __slots__ 属性

2 6-8 python中 __slots__

2019-11-24

qq_慕标3365427

这个任务放在这有点不太合适

0 2-9 python中闭包

2019-11-21

慕瓜2459498

看不懂得童鞋可以看看这个通俗易懂的例子：https://www.jb51.net/article/158814.htm

1 2-12 python中编写无参数decorator

2019-11-19

慕粉1126521984

def cmp_ignore_case(s1, s2):
if s1.upper() > s2.upper():
return 1
if s1.upper() < s2.upper():
return -1
return 0

print sorted(['bob', 'about', 'Zoo', 'Credit'], cmp_ignore_case)

0 2-7 python中自定义排序函数

2019-11-18

hen_nam

def is_sqr(x):
y = math.sqrt(x)
return y == int(y)

0 2-6 python中filter()函数

2019-11-17

Andrew_Louis

L2 = sorted(L1,key = lambda x : x.name)

2 4-3 python中创建实例属性

2019-11-14

慕粉1126521984

def prod(x, y):
return x*y

print reduce(prod, [2, 4, 5, 7, 12])

2 2-5 python中reduce()函数

2019-11-11

慕粉1126521984

def format_name(s):
return s.capitalize()

print map(format_name, ['adam', 'LISA', 'barT'])

2 2-4 python中map()函数

2019-11-11

慕桂英4384466

def prod(x,y):
return x*y
def reduce_prod(lst):
return reduce(prod,lst)
def calc_prod(lst):
def calc_prod():
return reduce_prod(lst)
return calc_prod

f = calc_prod([1, 2, 3, 4])
print f()

1 2-8 python中返回函数

2019-11-02