return mysqli_insert_id(connect())
function insert($table,$array){
$array['password'] = md5($array['password'] );
$keys = join(",",array_keys($array));
$vals = "'".join("','",array_values($array))."'";
$sql = "insert {$table}($keys) values({$vals})";
mysqli_query(connect(),$sql);
return mysqli_insert_id(connect());
}
该方法为何一直返回0?
在这调用
function addAdmin(){
$arr = $_POST;
if(insert("imooc_admin",$arr)){
$mes = "添加成功!<br/><a href='addAdmin.php'>继续添加</a>|<a href ='listAdmin.php'>查看管理员</a>";
}else{
$mes = "添加失败!<br/><a href='addAdmin.php'>重新添加</a>";
}
return $mes;
}