结果为什么是整数形式

import math

def quadratic_equation(a, b, c):
    m == 0.0
    n== 0.0
    if b**2 - 4*a*c > 0:
        m = (-b + (b**2 - 4*a*c)**1/2)*1/(2*a)
        n = (-b - (b**2 - 4*a*c)**1/2)*1/(2*a)
    elif b**2 - 4*a*c == 0:
        m == n == -b/(2*a)
    else:
        none
    return m,n

print quadratic_equation(2, 3, 0)
print quadratic_equation(1, -6, 5)

为什么这样的结果是正确答案的整数形呀？？怎么样改可以变成小数形式？？

耶耶耶3983892

2016-09-27

源自：初识Python 7-4

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4 回答

MH__Linux
2016-10-25

def quadratic_equation(a, b, c):

    if b**2 - 4*a*c > 0:
        m = (-b + (b**2 - 4*a*c)**1/2)*1/(2*a)
        n = (-b - (b**2 - 4*a*c)**1/2)*1/(2*a)
    elif b**2 - 4*a*c == 0:
        m == n == -b/(2*a)
    else:
        none
    return m,n
print quadratic_equation(2.0, 3, 0)
print quadratic_equation(1.0, -6, 5)

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qq_疯子_105
2016-09-27

import math

def quadratic_equation(a, b, c):

m = 0.0

n= 0.0

if b**2 - 4*a*c > 0:

m = (-b + (b**2 - 4*a*c)**1/2)*1/(2*a)

n = (-b - (b**2 - 4*a*c)**1/2)*1/(2*a)

elif b**2 - 4*a*c == 0:

m == n == -b/(2*a)

else:

none

return m,n

print (quadratic_equation(2, 3, 0))

print (quadratic_equation(1, -6, 5))

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MacroPan
2016-09-27

import math

def quadratic_equation(a, b, c):
    m = 0.0
    n = 0.0
    if b**2 - 4*a*c > 0:
        m = (-b + (b**2 - 4*a*c)**1/2)*1.0/(2*a)  //关键是乘以1.0就可以做一次类型转化了
        n = (-b - (b**2 - 4*a*c)**1/2)*1.0/(2*a)  
    elif b**2 - 4*a*c == 0:
        m == n == -b/(2*a)
    else:
        none
    return m,n

print quadratic_equation(2, 3, 0)
print quadratic_equation(1, -6, 5)

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