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错误求解答

总是提示我You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ')  WHERE id = 1' at line 1

但是我反复对着视频看了好几遍,都一样啊

public void updateGoddess(Goddess g) throws Exception{

Connection conn = DBUtil.getConnection();

String sql = " UPDATE imooc_goddess " + " SET user_name=?,sex=?,age=?,birthday=?,email=?,mobile=?," +

" update_user=?,update_date=current_date(),isdel=?) " + " WHERE id = ? ";

PreparedStatement ptmt = conn.prepareStatement(sql);

ptmt.setString(1, g.getUser_name());

ptmt.setInt(2, g.getSex());

ptmt.setInt(3, g.getAge());

ptmt.setDate(4, new Date(g.getBirthday().getTime()));

ptmt.setString(5, g.getEmail());

ptmt.setString(6,g.getMobile());

ptmt.setString(7, g.getUpdate_user());

ptmt.setInt(8, g.getIsdel());

ptmt.setInt(9, g.getId());

ptmt.execute();

}

调用:

public static void main(String[] args) throws Exception {

GoddessDao g = new GoddessDao();

/*

* List<Goddess> gs = g.query();

  for (Goddess goddess : gs) {

  System.out.println(goddess.getUser_name() + "," + goddess.getAge());

  }

*/

        Goddess g1 = new Goddess();

        g1.setUser_name("黄蓉");

        g1.setSex(1);

        g1.setAge(20);

        g1.setBirthday(new Date());

        g1.setEmail("12344870@qq.com");

        g1.setMobile("54354435151");

      

      

        g1.setUpdate_user("dlsd");

        g1.setIsdel(1);

        

        g1.setId(1);

        

       g.updateGoddess(g1);


正在回答

1 回答

isdel=?)  多了一个括号

0 回复 有任何疑惑可以回复我~
#1

旗开得胜wds 提问者

非常感谢!
2016-11-30 回复 有任何疑惑可以回复我~

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