这种写法怎么报错!
var hsh = function(){
return {
init: function(){
//ajax 默认设置
$.ajaxSetting({
type: "post",
url: apiUrl,
dataType : "json",
async: true,
error: function(xhr, errorType, error){
},
beforeSend: function(xhr, setting){
},
success: function(data, status, xhr){
},
complete: function(xhr, status){
}
});
alert("init");
//init.End
},
home: function(){
alert("home");
}
}
}();前台调用:
<script src="//cdn.staticfile.org/zepto/1.1.4/zepto.min.js"></script>
<script src="./assets/js/script.js"></script>
<script>
$(function(){
hsh.home();
hsh.init();
});
</script>报错:
TypeError: $.ajaxSetting is not a function
求解?
