ContextMenu的点击事件
@Override
public boolean onContextItemSelected(MenuItem item) {
switch (item.getItemId()){
case 101:
Toast.makeText(this, "我点击了新建", Toast.LENGTH_SHORT).show();
break;
case 102:
Toast.makeText(this, "我点击了复制", Toast.LENGTH_SHORT).show();
break;
case 103:
Toast.makeText(this, "我点击了剪切", Toast.LENGTH_SHORT).show();
break;
case 104:
Toast.makeText(this, "我点击了删除", Toast.LENGTH_SHORT).show();
break;
}
return super.onContextItemSelected(item);
}如上，ContextMenu既然是长按某个item，那我如何拿到我要操作的那个Item对象，或者说如何确定ListView的position呢？
