如何将json串如下:{"1":[{"id":6397891,"rate":81,"type":2,"unitId":1,"userId":7133}, {"id":6397882,"rate":72,"type":1,"unitId":1,"userId":7133}],"2":[{"id":6397906,"rate":90,"type":1,"unitId":2,"userId":7133}]}转换为:Map<String, List<Unit>> 类型通过jackson,fastjson,jsoblib都可以,求指点!
3 回答
芜湖不芜
TA贡献1796条经验 获得超7个赞
public static Map<String, Object> jsonToMap(JSONObject json) throws JSONException {
Map<String, Object> retMap = new HashMap<String, Object>();
if(json != JSONObject.NULL) {
retMap = toMap(json);
}
return retMap;
}
public static Map<String, Object> toMap(JSONObject object) throws JSONException {
Map<String, Object> map = new HashMap<String, Object>();
Iterator<String> keysItr = object.keys();
while(keysItr.hasNext()) {
String key = keysItr.next();
Object value = object.get(key);
if(value instanceof JSONArray) {
value = toList((JSONArray) value);
}
else if(value instanceof JSONObject) {
value = toMap((JSONObject) value);
}
map.put(key, value);
}
return map;
}
public static List<Object> toList(JSONArray array) throws JSONException {
List<Object> list = new ArrayList<Object>();
for(int i = 0; i < array.length(); i++) {
Object value = array.get(i);
if(value instanceof JSONArray) {
value = toList((JSONArray) value);
}
else if(value instanceof JSONObject) {
value = toMap((JSONObject) value);
}
list.add(value);
}
return list;
}
冉冉说
TA贡献1877条经验 获得超1个赞
哈哈,看来已经来晚了啊...题主已经采纳答案了嘛,不过lamdba的方式还是要强烈安利给题主哈,因为代码简单的很多(用的fastjson哈,不过其他应该也差不多)
思路就是,题主的json字符串其实总得来说就是一个key-value的形式,应该是满足了最终题主想要的Map<String, List<Unit>>的结构了,所以直接一个Collectors.toMap就搞定啦
Map<String, List<Unit>> result = JSONObject.parseObject(s)
.entrySet().stream()
.collect(Collectors.toMap(Map.Entry::getKey, entry -> JSONObject.parseArray(String.valueOf(entry.getValue()), Unit.class)));
然后...就完了噻...就这么点代码...(s就是你那个json字符串哈)
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