shell脚本 怎么获取xml内容的标签属性值？

Question

<?xml version="1.0" encoding="UTF-8"?><api xmlns="http://ws.apache.org/ns/synapse" name="provider--appa" context="/apraa" version="1.0.0" version-type="url"><resource methods="DELETE POST PUT GET" url-mapping="/*">......我想获取api标签内的name的值和context的值和version的值，赋给变量，后面要用的。

Answer 1

a=`awk '{for(i=1;i<=NF;i++)printf $i"\n";printf "\n"}' aa | grep "name=" |awk -F= '{print $2}'`;echo $a
b=`awk '{for(i=1;i<=NF;i++)printf $i"\n";printf "\n"}' aa | grep "context=" |awk -F= '{print $2}'`;echo $b
c=`awk '{for(i=1;i<=NF;i++)printf $i"\n";printf "\n"}' aa | grep "version=" |awk -F= '{print $2}'`;echo $c
这里有两个version

Answer 2

1	sed -nr '/task id/{s/.*<task id="([^"]+)"\sbusiness="([^"]+)".*/\1,\2/;p}' test.xml

或者：

1	awk '/task id/{split($0,a,"(=\")|(\" )");print a[2]","a[4]}' test.xml

 或者：

1	sed -n '/task id/{s/"//g;s/^ *//;p}' test.xml | awk -F"[= ]" '{print $3","$5}'