目前正在做关于UInt8数组的相关应用，遇到问题。我的代码：@interface MyClass : NSObject {
__strong id * myArray; //private byte[] myArray; <- Java code
}
@property (nonatomic,readwrite) __strong id * myArray;
@end在MyClass中的方法：-(int) getArray: (__strong id *) bufferTmp {
NSString* aString = @"theString";
int bytes = aString.length;
//now I need to fill the passed in array with the chars of the String
for (int i = 0; i < bytes; i++) {
char c = [aString characterAtIndex:i];
??? bufferTmp[i] = (UInt8)c; <----- what to write here?
}
return bytes;
}下面是我准备调用方法充填myBuffer的代码：UInt8 myBuffer[10000];
[xxx read: myBuffer]; <- 不知道这段正确么?这是相同的java代码：public int getArray(byte[] bufferTmp) {
String theString = "theString";
for (int i = 0; i < bytes; i++) {
char c = theString.charAt(i);
bufferTmp[i] = (byte) c;
}
return bytes;
}在java中调用方法的代码：byte[] myBuffer = new byte[10000];
int n = read(myBuffer);
1 回答
千巷猫影
TA贡献1829条经验 获得超7个赞
在Objective-C中可以使用NSDate对象当做byte buffer, 然后dataUsingEncoding获取字节表示的字符串：
NSString *aString = @"theString"; NSData *myBuffer = [aString dataUsingEncoding:NSUTF8StringEncoding]; const char *bytes = [myBuffer bytes]; // pointer to the bytes in the buffer NSUInteger count = [myBuffer length]; // number of bytes in the buffer
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