如何在大空间尺度上加速A *算法？

Question

如何在大空间尺度上加速A *算法？从http://ccl.northwestern.edu/netlogo/models/community/Astardemo，我通过使用网络中的节点来定义最低成本路径来编码A *算法。代码似乎有效，但是当我在大空间尺度上使用它时它太慢了。我的景观有1000个补丁x 1000个补丁，1个补丁= 1个像素。即使我减少400补丁x 400补丁1补丁= 1像素，它仍然太慢（我不能修改我的景观低于400补丁x 400补丁）。这是代码：to find-path [ source-node destination-node] let search-done? falselet search-path []let current-node 0set list-open []set list-closed []  let list-links-with-nodes-in-list-closed []let list-links []set list-open lput source-node list-openwhile [ search-done? != true][    ifelse length list-open != 0[  set list-open sort-by [[f] of ?1 < [f] of ?2] list-open   set current-node item 0 list-open   set list-open remove-item 0 list-open   set list-closed lput current-node list-closed  ask current-node  [      if parent-node != 0[    set list-links-with-nodes-in-list-closed lput link-with parent-node list-links-with-nodes-in-list-closed     ]    ifelse any? (nodes-on neighbors4) with [ (xcor = [ xcor ] of destination-node) and (ycor = [ycor] of destination-node)]    [      set search-done? true     ]    [              ask (nodes-on neighbors4) with [ (not member? self list-closed) and (self != parent-node) ]        [          if not member? self list-open and self != source-node and self != destination-node        [          set list-open lput self list-open          set parent-node current-node          set list-links sentence (list-links-with-nodes-in-list-closed) (link-with parent-node)          set g sum (map [ [link-cost] of ? ] list-links)          set h distance destination-node           set f (g + h)        ]      ]    ]  ]][  user-message( "A path from the source to the destination does not exist." )  report [] ]]set search-path lput current-node search-pathlet temp first search-pathwhile [ temp != source-node ][ ask temp[  set color red]不幸的是，我不知道如何加快这段代码。是否有解决方案在大空间尺度上快速计算最低成本路径？