bash中两个数组的比较/差异

Question

是否有可能采取bash中两个数组的差异。如果您可以建议我这样做的话，那真的很棒。代码：Array1=( "key1" "key2" "key3" "key4" "key5" "key6" "key7" "key8" "key9" "key10" )Array2=( "key1" "key2" "key3" "key4" "key5" "key6" ) Array3 =diff(Array1, Array2)Array3 ideally should be :Array3=( "key7" "key8" "key9" "key10" )感谢您的帮助。

Answer 1

echo ${Array1[@]} ${Array2[@]} | tr ' ' '\n' | sort | uniq -u

输出量

key10

key7

key8

key9

您可以根据需要添加排序

Answer 2

每当出现一个问题，处理可能无法排序的唯一值时，我的脑子立刻就醒悟。这是我的看法。

码

#!/bin/bash

diff(){

  awk 'BEGIN{RS=ORS=" "}

       {NR==FNR?a[$0]++:a[$0]--}

       END{for(k in a)if(a[k])print k}' <(echo -n "${!1}") <(echo -n "${!2}")

}

Array1=( "key1" "key2" "key3" "key4" "key5" "key6" "key7" "key8" "key9" "key10" )

Array2=( "key1" "key2" "key3" "key4" "key5" "key6" )

Array3=($(diff Array1[@] Array2[@]))

echo ${Array3[@]}

输出量

$ ./diffArray.sh

key10 key7 key8 key9

*注意**：像给出的其他答案一样，如果数组中有重复的键，则它们只会被报告一次；这可能是或不是您正在寻找的行为。用于处理该问题的awk代码更加混乱，而且不够干净。