这段代码失败了我在数据库中有一个现有的版本化值,我使用 获取该值entity manager.find并在实体上设置。VersionEntity version = entityManager.find(VersionEntity.class, 1);entities.forEach(__ -> __.setVersion(version));entities.forEach(entityManager::persist);entityManager.flush();我专门查找并分配版本 1,那么为什么它甚至会尝试使用版本 2。我什至尝试过merge,但没有奏效。我的属性显然是错误的/不正确的。刷新失败本地异常堆栈:异常 [EclipseLink-4002](Eclipse 持久性服务 - 2.7.1.qualifier):org.eclipse.persistence.exceptions.DatabaseException 内部异常:org.postgresql.util.PSQLException:错误:插入或更新表“ t_quality_measurement”违反外键约束“fk_t_quality_measurement_version” 详细信息:表“t_version”中不存在键(版本)=(2)。错误代码:0 调用:INSERT INTO T_QUALITY_MEASUREMENT (BRAND, DATE, KPICODE, KPICOMPAREVW, KPICOMPAREWT, KPIVALUE, ORGANISATIONUNIT, PHASE, PLANT, SERIES, SIGNALCOLOR, TECHNOLOGY, TEMPORALUNIT, (?, S?) ?, ?, ?, ?, ?, ?, ?, ?, ?) bind => [14 个参数绑定] 查询:当我专门查找 1 时,我不确定为什么它会尝试使用 2。@Entity@Table(name = "T_QUALITY_MEASUREMENT")public class QualityMeasurementEntity extends Versioned implements Serializable { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) @Column(columnDefinition = "serial") private Integer id; @Column(length = 100) private String series;版本化看起来像这样@MappedSuperclasspublic abstract class Versioned { @ManyToOne @JoinColumn(name = "version", insertable = false, updatable = false) protected VersionEntity version = null; public VersionEntity getVersion() { return version; } public void setVersion(VersionEntity version) { this.version = version; }}和版本实体。@Entity@Table(name = "T_VERSION", indexes = { @Index(name = "pk_version", columnList = "id", unique = true)})@NamedQuery(name = "Version.findById", query = "SELECT v FROM VersionEntity v WHERE v.id = :id")public class VersionEntity { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) @Column(columnDefinition = "serial") private Integer id; @Column(name = "CREATED") private LocalDateTime created;
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