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如果需要函数指针数组接收参数,这个该怎么操作呢?

如果需要函数指针数组接收参数,这个该怎么操作呢?

MM们 2021-07-26 20:18:17
class Base{private:int x;int y;public:Base();Base(int x,int y);virtual void draw();void move();};class Poit :virtual public Base{public:Poit();Poit(int x,int y);void draw();};class Line :virtual public Base{private:int a;int b;public:Line();Line(int a,int b,int x,int y);void draw();};class Circle :virtual public Base{private:int r;public:Circle();Circle(int x,int y,int r);void draw();};class Graphics :public Poit,public Line, public Circle{private:static int i;void (*pf[6])();public:void task(Poit *p); void task(Line *l);void task(Circle *c);void draw();};int Graphics::i=0;#include <iostream.h>#include "Graphics.h"Base::Base(){x=0;y=0;}Base::Base(int x,int y){this->x=x;this->y=y;}void Base::move(){cout<<"将画笔移动到("<<x<<","<<y<<"),";}Poit::Poit():Base(0,0){}Poit::Poit(int x,int y):Base(x,y){}void Poit::draw(){Base::move();cout<<"画一个点"<<endl;}Line::Line():Base(0,0){a=0;b=0;}Line::Line(int a,int b,int x,int y):Base(x,y){this->a=a;this->b=b;}void Line::draw(){Base::move();cout<<"画一条到("<<a<<","<<b<<")的直线"<<endl;}Circle::Circle():Base(0,0){r=0;}Circle::Circle(int x,int y,int r):Base(x,y){this->r=r;}void Circle::draw(){Base::move();cout<<"画一个半径"<<r<<"的圆"<<endl;}void Graphics::draw(){int n;for(n=0;n<i;n++){cout<<"第"<<n<<"步:";(*pf[i])();}}void Graphics::task(Poit *p){pf[i]=p->draw;}void Graphics::task(Line *l){pf[i]=l->draw;}void Graphics::task(Circle *c){pf[i]=c->draw;}#include <iostream.h>#include "Graphics.h"int main(){Graphics g;g.task(new Poit(3,5));return 0;}
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2 回答

?
缥缈止盈

TA贡献2041条经验 获得超4个赞

#include <stdio.h>
void print(char *srt)
{
printf("%s\n",srt);
}
void (*p)(char *str);//函数指针
int main()
{
p=print;//把要指向的函数给函数指针
p("Hello World!");//传进参数
return 0;
}
//简单例子

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反对 回复 2021-07-29
?
叮当猫咪

TA贡献1776条经验 获得超12个赞

void (*array[10])(void)
array[10]--->就是函数指针数组
将对应的函数名赋值给数组就可以了

比如这么个函数
int fun(int a)

array[0] = fun;
就这样就可以了。
你试试吧



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反对 回复 2021-07-29
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