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如何解决:每次用户单击按钮时都会重置 CSS 动画

如何解决:每次用户单击按钮时都会重置 CSS 动画

DIEA 2021-12-02 19:45:53
我的页面上有 3 个按钮(男性、女性、非性别),这些按钮会导致字符在页面上弹跳。当前,当用户单击第二个按钮时,第一个按钮的字符会不断弹跳。我如何做到只有一个按钮的字符会弹跳?下面的 JavaScript 代码:const allDivs = Array.from(document.querySelectorAll('div'))const mainHeader = document.querySelector('header')let maleButton = document.createElement('button')maleButton.textContent = 'Male Characters'maleButton.addEventListener('click', () => {    maleCharacters.forEach(character => {        let matchedDiv = allDivs.find((oneDiv) => {            return oneDiv.firstChild.textContent === character.name        })        //matchedDiv.setAttribute("style", "display: none;")        matchedDiv.className = 'animated infinite bounce delay-2s'    })});let femaleButton = document.createElement('button')femaleButton.textContent = 'Female Characters'femaleButton.addEventListener('click', () => {    femaleCharacters.forEach(character => {        let matchedDiv = allDivs.find((oneDiv) => {            return oneDiv.firstChild.textContent === character.name        })        //matchedDiv.setAttribute("style", "display: none;")        matchedDiv.className = 'animated infinite bounce delay-2s;'    })});let otherButton = document.createElement('button')otherButton.textContent = 'Non-Gender Characters'otherButton.addEventListener('click', () => {    otherCharacters.forEach(character => {        let matchedDiv = allDivs.find((oneDiv) => {            return oneDiv.firstChild.textContent === character.name        })        //matchedDiv.setAttribute("style", "display: none;")        matchedDiv.className = 'animated infinite bounce delay-2s;'    })});mainHeader.appendChild(maleButton)mainHeader.appendChild(femaleButton)mainHeader.appendChild(otherButton)
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2 回答

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GCT1015

TA贡献1827条经验 获得超4个赞

这很粗糙,因为我没有完整的代码,但大致如下:


const allDivs = Array.from(document.querySelectorAll('div'))


const mainHeader = document.querySelector('header')


function clearAnimations() {

  [maleCharacters, femaleCharacters, otherCharacters].forEach(c => 

    c.forEach(character => allDivs.find((oneDiv) => 

      oneDiv.firstChild.textContent === character.name).className = '';

  });

}


let maleButton = document.createElement('button')

maleButton.textContent = 'Male Characters'

maleButton.addEventListener('click', () => {

    clearAnimations();

    maleCharacters.forEach(character => {

        let matchedDiv = allDivs.find((oneDiv) => {

            return oneDiv.firstChild.textContent === character.name

        })

        //matchedDiv.setAttribute("style", "display: none;")

        matchedDiv.className = 'animated infinite bounce delay-2s'

    })

});


let femaleButton = document.createElement('button')

femaleButton.textContent = 'Female Characters'

femaleButton.addEventListener('click', () => {

    clearAnimations();

    femaleCharacters.forEach(character => {

        let matchedDiv = allDivs.find((oneDiv) => {

            return oneDiv.firstChild.textContent === character.name

        })

        //matchedDiv.setAttribute("style", "display: none;")

        matchedDiv.className = 'animated infinite bounce delay-2s;'

    })

});


let otherButton = document.createElement('button')

otherButton.textContent = 'Non-Gender Characters'

otherButton.addEventListener('click', () => {

    clearAnimations();

    otherCharacters.forEach(character => {

        let matchedDiv = allDivs.find((oneDiv) => {

            return oneDiv.firstChild.textContent === character.name

        })

        //matchedDiv.setAttribute("style", "display: none;")

        matchedDiv.className = 'animated infinite bounce delay-2s;'

    })

});


mainHeader.appendChild(maleButton)

mainHeader.appendChild(femaleButton)

mainHeader.appendChild(otherButton)


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反对 回复 2021-12-02
?
鸿蒙传说

TA贡献1865条经验 获得超7个赞

您需要使用“this”,如果您的按钮在“div”中,请尝试编写:

 this.parentElement.className = 'animated infinite bounce delay-2s;

代替:

 matchedDiv.className = 'animated infinite bounce delay-2s;'


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反对 回复 2021-12-02
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