main函数体中一个字也不要更改，并满足以下的条件，该怎么实现呢？

Question

公司中有两类人员：一般雇员（Employee）和经理（Manager）。每位雇员都有各自的基本信息，包括姓名、年龄、工龄、部门名称。每位经理除了具有这些基本信息外，还具有另外两个信息：职务级别、他所管辖的雇员信息。请设计并实现两个类，分别表示雇员和经理两类人员，并满足以下程序给出的运行结果（注意：经理也是雇员）。int main(){Employee e1(“Jack”, 24, 2, “Development”);Employee e2(“Susan”, 28, 4, “Development”);Manager m(“Tom”, 30, 2, “Development”, 2);m.addMember(&e1).addMember(&e2);e1.printOn(); // display all data member information of Jacke2.printOn(); // display all data member information of Susamm.printOn(); // display all data member information of Tomcout << “Total” << Employee::count();cout<< “employee’s object created.” << endl;return 0;}程序运行结果：This is Jack:age: 24Year: 2Dept: DevelopmentThis is Susan:age: 28Year: 4Dept: DevelopmentThis is Tom:age: 30Year: 2Dept: DevelopmentLevel: 2Members: Jack SusanTotal 3 employee’s object created.1.main函数体中一个字也不要更改2.这是我们的作业题，有人重复问也正常。

Answer 1

#include<iostream>
#include<cstdlib>
#include<string>
using namespace std;
class Employee{
public:
Employee(char *,int,int,char *);
void printOn();
static int count(); //调用静态成员的函数也必须是静态函数
char *name;
int age;
int worktime;
char *department;
static int n;
/*~Employee(){
delete name;
delete department;
}*/ //使用该析构函数会抱内存错
};
int Employee::n=0;
Employee::Employee(char *name,int age,int worktime,char *department){
this->name=name;
this->age=age;
this->worktime=worktime;
this->department=department;
n++;
}
void Employee::printOn(){
cout<<"This is "<<name<<endl
<<"age "<<age<<endl
<<"year "<<worktime<<endl
<<"Dept "<<department<<endl;
}
int Employee::count(){
return n;
};
class Manager:public Employee{
public:
Manager(char *,int,int,char *,int);
Manager& addMember(Employee *);
void printOn();
private:
static int m;
int level;
char *member[10];
};
int Manager::m=0;
Manager::Manager(char *name,int age,int worktime,char *department,int level):Employee(name,age,worktime,department){
this->level=level;
}
Manager& Manager::addMember(Employee *e){
member[m++]=e->name;
return *this;
}
void Manager::printOn(){
Employee::printOn();
cout<<"Level: "<<level<<endl
<<"Members: ";
for(int i=0;i<n-1;i++)
cout<<member[i]<<" ";
cout<<endl;
}
int main(){
Employee e1("Jack", 24, 2, "Development");
Employee e2("Susan", 28, 4, "Development");
Manager m("Tom", 30, 2, "Development", 2);
m.addMember(&e1).addMember(&e2);
e1.printOn(); // display all data member information of Jack
e2.printOn(); // display all data member information of Susam
m.printOn(); // display all data member information of Tom
cout << "Total " << Employee::count();
cout<< " employee's object created." << endl;
system("pause");
return 0;
}

Answer 2

#include<iostream>
using namespace std;
/*
公司中有两类人员：一般雇员（Employee）和经理（Manager）。
每位雇员都有各自的基本信息，包括姓名、年龄、工龄、部门名称。
每位经理除了具有这些基本信息外，还具有另外两个信息：
职务级别、他所管辖的雇员信息。请设计并实现两个类，分别表示雇
员和经理两类人员，并满足以下程序给出的运行结果（注意：经理也是雇员）。
*/
class Employee
{
char* _xm;
int _nl;
int _gl;
char* _bm;
static int _n;
public:
void getXm(char*&);
Employee(char*, int, int, char*);
virtual ~Employee();
virtual void printOn();
static int count();
};
void Employee::getXm(char*& xm)
{
strcpy(xm,_xm);
}
int Employee::_n=0;
Employee::Employee(char* xm,int nl, int gl, char* bm)
{
++_n;
_xm=new char[strlen(xm)+1];
strcpy(_xm, xm);
_nl=nl;
_gl=gl;
_bm=new char[strlen(bm)+1];
strcpy(_bm, bm);
}
Employee::~Employee()
{
if(_xm!=NULL)
delete [] _xm;
if(_bm!=NULL)
delete [] _bm;
}
void Employee::printOn()
{
cout<<"This is "<<_xm<<": "<<endl;
cout<<"age: "<<_nl<<endl;
cout<<"Year: "<<_gl<<endl;
cout<<"Dept: "<<_bm<<endl;
}
int Employee::count()
{
return _n;
}

class Manager : public Employee
{
int _dj;
char* _gyxx;
public:
Manager(char*, int, int, char*, int);
virtual ~Manager();
void printOn();
Manager& addMember(Employee*);
};
Manager::Manager(char* xm, int nl, int gl, char* bm,int dj)
:Employee(xm, nl, gl, bm)
{
_gyxx=NULL;
_dj=dj;
}
Manager::~Manager()
{
if(_gyxx!=NULL)
delete [] _gyxx;
}
void Manager::printOn()
{
Employee::printOn();
cout<<"Level: "<<_dj<<endl;
cout<<"Members: "<<_gyxx<<endl;
}
Manager& Manager::addMember(Employee* e)
{
char* a=new char[50];
e->getXm(a);
if(_gyxx!=NULL)
{

char* t=new char[strlen(_gyxx)+1];
strcpy(t, _gyxx);
delete [] _gyxx;
_gyxx=new char[strlen(t)+strlen(a)+6];
strcpy(_gyxx, t);
strcat(_gyxx, " ");
strcat(_gyxx, a);
delete [] t;
}
else
{
_gyxx= new char[strlen(a)+1];
strcpy(_gyxx, a);
}
delete [] a;
return *this;
}

int main()
{
Employee e1("Jack", 24, 2, "Development");
Employee e2("Susan", 28, 4, "Development");
Manager m("Tom", 30, 2, "Development", 2);
m.addMember(&e1).addMember(&e2);
e1.printOn(); // display all data member information of Jack
e2.printOn(); // display all data member information of Susam
m.printOn(); // display all data member information of Tom
cout << "Total " << Employee::count();
cout<< " employee’s object created." << endl;
return 0;
}

Answer 3

//VC编译通过.输出完全一样.

#include<iostream>
#include<string.h>
using namespace std;
class Employee
{
private:
char eName[20];//姓名
int eAge;//年龄
int eWorkAge;//工龄
char eDepName[20];//部门名称
static int eCount;
public:
Employee(char *name,int age,int year,const char *dep="Development")
{
strcpy(eName,name);
strcpy(eDepName,dep);
eAge=age;
eWorkAge=year;
eCount++;
}
~Employee()
{
eCount--;
};
char *name(){return eName;}
void printOn()
{
cout<<"This is "<<eName<<endl;
cout<<"age: "<<eAge<<endl;
cout<<"Year: "<<eWorkAge<<endl;
cout<<"Dept: "<<eDepName<<endl;
}
int count(){return eCount;}
};
int Employee::eCount=0;
class Manager:public Employee
{
private:
int level;//职务级别
char *inCharge;
public:
Manager(char *name,int age,int year,const char *dep="Development",int lv=2):Employee(name,age,year,dep)
{
level=lv;
inCharge=NULL;
}
~Manager()
{
if(inCharge!=NULL) delete inCharge;
}
void printOn()
{
Employee::printOn();
cout<<"level: "<<level<<endl;
cout<<"Members: "<<inCharge<<endl;

}

int addMember(Employee* Member)
{

int len1=inCharge==NULL?0:strlen(inCharge);
int len2=strlen(Member->name());
char *p=new char[len1+len2+2];
if(inCharge!=NULL) strcpy(p,inCharge);

p[len1]=' ';
strcpy(p+len1+1,Member->name());
if(inCharge!=NULL) delete inCharge;
inCharge=p;

return 1;
}

};

int main()
{
Employee e1("Jack", 24, 2, "Development");
Employee e2("Susan", 28, 4, "Development");
Manager m("Tom", 30, 2, "Development", 2);

m.addMember(&e1);
m.addMember(&e2);

e1.printOn();// display all data member information of Jack
e2.printOn();// display all data member information of Susam
m.printOn();// display all data member information of Tom
cout << "Total" << e1.count();
cout<< "employee’s object created." << endl;

return 0;
}