我用buffer+1，输出来是地址，这是不对的把？

Question

现有一个txt。每行仅有一个词：No.10.000000192.168.0.100192.168.0.102TCP4480>commplex-link[SYN]Seq0Win64240Len0MSS1460SACK_PERM=1用ifstream读入该txt，循环getline存入buffer，当buffer为'No.'时，下一行数据'1'赋值给int num，下下行数据”0.000000“赋值给float time；当buffer为'Seq'时，下一行数据'0'赋值给int seq；当buffer为'Win'时，下一行数据'64240'赋值给int win；当buffer为'Len'时，下一行数据'0'赋值给int len。我用buffer+1，输出来是地址，不对。我本来就对输入输出流不是很理解，跪求能人解答。

Answer 1

#include<iostream>
#include<fstream>
#include<string>
#include<iomanip>
#include<assert.h>
using namespace std;

void main()
{
char buffer[50];
ifstream inf("E:\\test\\test.txt");
assert(inf);
int num,seq,win,len;
float time;
while(inf.getline(buffer,50))
{
if(strcmp(buffer,"No.")==0)
{
if(inf.getline(buffer,50))
num=atoi(buffer);
if(inf.getline(buffer,50))
time=atof(buffer);
}
if(strcmp(buffer,"Seq")==0)
{
if(inf.getline(buffer,50))
seq=atoi(buffer);
}
if(strcmp(buffer,"Win")==0)
{
if(inf.getline(buffer,50))
win=atoi(buffer);
}
if(strcmp(buffer,"Len")==0)
{
if(inf.getline(buffer,50))
len=atoi(buffer);
}
}
inf.close();
cout<<"num:"<<num<<endl;
cout<<setiosflags(ios::fixed)<<setprecision(6)<<"time:"<<time<<endl;
cout<<"seq:"<<seq<<endl;
cout<<"win:"<<win<<endl;
cout<<"len:"<<len<<endl;
}

Answer 2

buffer 用pointer 不要用数组
你仔细复习一下pointer的用法，
int *p = 1;
cout << p <<endl;
cout << *p <<endl; 出来的是不一样的东西。