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TA贡献1842条经验 获得超22个赞
这是一个关于如何使用 postgres 的ON CONFLICT DO NOTHING示例to_sql
# import postgres specific insert
from sqlalchemy.dialects.postgresql import insert
def to_sql_on_conflict_do_nothing(pd_table, conn, keys, data_iter):
# This is very similar to the default to_sql function in pandas
# Only the conn.execute line is changed
data = [dict(zip(keys, row)) for row in data_iter]
conn.execute(insert(pd_table.table).on_conflict_do_nothing(), data)
conn = engine.connect()
df.to_sql("some_table", conn, if_exists="append", index=False, method=to_sql_on_conflict_do_nothing)

TA贡献1854条经验 获得超8个赞
我刚刚遇到了类似的问题,然后对于这个答案,我想出了如何发送df到的解决方案potgresSQL ON CONFLICT:
1.发送一些初始数据到数据库创建表
from sqlalchemy import create_engine
engine = create_engine(connection_string)
df.to_sql(table_name,engine)
2.添加primary key
ALTER TABLE table_name ADD COLUMN id SERIAL PRIMARY KEY;
3. 在要检查唯一性的列(或列)上准备索引
CREATE UNIQUE INDEX review_id ON test(review_id);
4.映射sql表sqlalchemy
from sqlalchemy.ext.automap import automap_base
ABase = automap_base()
Table = ABase.classes.table_name
Table.__tablename__ = 'table_name'
6. 做你insert on conflict的:
from sqlalchemy.dialects.postgresql import insert
insrt_vals = df.to_dict(orient='records')
insrt_stmnt = insert(Table).values(insrt_vals)
do_nothing_stmt = insrt_stmnt.on_conflict_do_nothing(index_elements=['review_id'])
results = engine.execute(do_nothing_stmt)
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