在 Python 中，如何获取一串平均值并对它们进行排序？

Question

player_avg是一个字符串，其中包含用逗号分隔的棒球运动员的击球率：player_avg = "0.209,0.305,0.265,0.175,0.324,0.215,0.362,0.178,0.273,0.309"如何编写代码来计算击球次数大于 0.299 的玩家数量，并将结果存储在变量中num_players_over_300？

Answer 1

这是列表理解的替代方法：

player_avg = "0.209,0.305,0.265,0.175,0.324,0.215,0.362,0.178,0.273,0.309"

num_players_over_300 = len([float(i) for i in player_avg.split(',') if float(i) > 0.299])

输出：4

Answer 2

将字符串拆分为列表，然后对其进行排序。仅获取超过 0.300 的值。

avg_list = sorted([float(avg) for avg in player_avg.split(',')])

players_over_300 = [avg for avg in avg_list if avg > 0.3]

num_players_over_300 = len(players_over_300)

Answer 3

这是你的代码

l= "0.209,0.305,0.265,0.175,0.324,0.215,0.362,0.178,0.273,0.309"

numberList = list(map(float,l.split(",")))

num_of_players=0

for i in numberList:

    if i>0.299:

        num_of_players+=1

print(num_of_players)

Answer 4

包含您可以学习的基本步骤的代码 -

>>> player_avg = "0.209,0.305,0.265,0.175,0.324,0.215,0.362,0.178,0.273,0.309"

>>> player_avg.split(',')

['0.209', '0.305', '0.265', '0.175', '0.324', '0.215', '0.362', '0.178', '0.273', '0.309']

>>> arr = player_avg.split(',')

>>> arr

['0.209', '0.305', '0.265', '0.175', '0.324', '0.215', '0.362', '0.178', '0.273', '0.309']

>>> op = []

>>> for i in arr:

...  if float(i) > 0.299:

...   op.append(float(i))

...

>>> op

[0.305, 0.324, 0.362, 0.309]

>>> op.sort()

>>> op

[0.305, 0.309, 0.324, 0.362]

>>>