根据工作日数获取工作日数组

Question

例如，如果我将周数传递为 3，我希望将数组排序为weekStartDayNumber = 3weekdays = ['wednesday', 'thursday', 'friday', 'saturday', 'sunday', 'monday', 'tuesday']如果我通过 week weekStartDayNumber 为 7 我希望数组按如下方式排序weekdays = ['sunday',...'saturday']该数组需要根据 weekStartDayNumber 进行排序。function days(weekStartDayNumber) { //logic here}

Answer 1

const weekDays = ['monday', 'tuesday','wednesday', 'thursday', 'friday', 'saturday', 'sunday']

const days = (n) =>

  // Splice will take out everything from where ever you want to start until 

  // the end of the array and remove that part from the original. So

  // weekdays only contains whatever is left. So simply add the rest

  // using concat

  weekDays.splice(n - 1, weekDays.length - n + 1).concat(weekDays);

Answer 2

let a = function SortByDay(startNum) {

    let weekDays = ['monday', 'tuesday', 'wednesday', 'thursday', 'friday', 'saturday', 'sunday']

    return weekDays

        .slice(startNum - 1)

        .concat(weekDays

        .slice(0, startNum - 1));

};

Answer 3

const days = (n) => [...weekdays.slice(n-1), ...weekdays.slice(0, n-1)]

这应该做你需要的。一个不错的小 ES6 单线。

Answer 4

使用Array.slice()：

function arrangeDays(startNum) {

    let days = ['monday', 'tuesday','wednesday', 'thursday', 'friday', 'saturday', 'sunday']

    let arrStart = days.slice(startNum-1)

    let arrEnd = days.slice(0, startNum-1)

    return arrStart.concat(arrEnd)

}

console.log(arrangeDays(3))

console.log(arrangeDays(7))