使用 Xor 在数组中查找重复项

Question

我有我创建的以下代码，但是我在如何将其调用到我的开发人员工具上的 console.log 以查看我的结果时遇到了问题。我是js新手...var num = [5,3,1,2,3,5,1];let duplicateValue = (num) => {    let countVal = 0;    for (let i = 0; i< num.lenght; i++){         countVal = countVal ^ num[i];}  return countVal; }控制台.log（重复值）；返回未定义.....

Answer 1

您拼写长度（长度）并且没有在控制台日志中调用方法

var num = [5,3,1,2,3,5,1];

let duplicateValue = (num) => {

    let countVal = 0;

    for (let i = 0; i< num.length; i++){

         countVal = countVal ^ num[i];}

  return countVal; 

 }

console.log(duplicateValue(num));

var num = [5,3,1,2,3,5,1];

let duplicateValue = (num) => {

    let countVal = 0;

    for (let i = 0; i< num.length; i++){

         countVal = countVal ^ num[i];}

  return countVal; 

 }

console.log(duplicateValue(num));

Answer 2

你需要这样安慰。您需要将数组作为参数传递。

console.log(duplicateValue([5,3,1,2,3,5,1]))

var num = [5,3,1,2,3,5,1];

let duplicateValue = (num) => {

    let countVal = 0;

    for (let i = 0; i< num.lenght; i++){

         countVal = countVal ^ num[i];}

  return countVal;

}

console.log(duplicateValue([5,3,1,2,3,5,1]));