如何将列表从一个函数传递到另一个函数？

Question

问题：玩弄在函数之间交换变量的想法。我正在执行以下代码：def benefits():    list =  ["Beautiful", "Explicit", "Simple", "Readability","Easy to share"]    return listdef statement(benefit):    print("The benifit is " + benefit )          def benefits_of_functions():      benefits_list = benefits()    for benefit in benefits_list:        print(statement(benefit))benefits_of_functions()我得到错误：The benifit is BeautifulNoneThe benifit is ExplicitNoneThe benifit is SimpleNoneThe benifit is ReadabilityNoneThe benifit is Easy to shareNone我无法理解“无”。你能帮我弄清楚为什么会出现在输出中吗？

Answer 1

在函数中返回而不是打印statement：

def benefits():

    list =  ["Beautiful", "Explicit", "Simple", "Readability","Easy to share"]

    return list

def statement(benefit):

    return "The benifit is " + benefit

def benefits_of_functions():  

    benefits_list = benefits()

    for benefit in benefits_list:

        print(statement(benefit))

benefits_of_functions()