3 回答
TA贡献1893条经验 获得超10个赞
首先,您应该在命令中打印内容,input()因为它会在 intent: 中被清除input("Text to display")。
其次,如果你想退出到主菜单,你需要打破每个嵌套循环。在这里你只打破最内层的循环。
在 Python 中没有goto指令也没有命名循环,您可以使用标志。当 used 按下“F”时,标志设置为 true,然后在每个外部嵌套循环的开头使用该标志来中断它们。它看起来像这样:
while True: # This is your menu loop
menuFlag = False # Declare and set the flag to False here
menu = input("Choose the menu: ")
# ...
while True: # Choose character loop
if menuFlag: break # Do not forget to break all outer loops
character = input("Choose a character: ")
# ...
while True: # Any other loop (choose weapon, ...)
weapon = input("Choose weapon: ")
# Here you want to return to the menu if f is pressed
# Set the flag to True in this condition
if weapon == "f":
menuFlag = True
break
在您的游戏中,这类似于:
goToMainMenu = False
while True:
if goToMainMenu: break
vocationchoice = input("Select vocation.\nPress P for Royal Paladin: ")
if vocationchoice == "P" or vocationchoice == "p":
#ask user to input magic level for paladin
num1 = float (input("Enter your magic level: "))
#ask for own training dummy
while True:
if goToMainMenu: break
trainingdummy = input("Do you have your own exercise dummy?\nType Y for yes and N for no: ")
if trainingdummy == "y" or trainingdummy == "Y":
#loop, where we ask user to input what exercise weapon they want to calculate
while True:
while True:
weaponchoice = input("Select exercise weapon:\n1. Training rod: ")
if weaponchoice == "q":
sys.exit() #quit the program
if weaponchoice == "1" or weaponchoice == "2" or weaponchoice == "3" or weaponchoice == "f":
break #break out of the input loop
#User choice
if weaponchoice == "1":
print("The amount of training rods needed for next magic level is " + str((nextmaglvlpalwithdummy(num1))) + ".")
if trainingdummy == "n" or trainingdummy == "N":
#list the different exercise weapon
#loop where ask user to input what exercise weapon they want to calculate
while True:
weaponchoice = input("Select exercise weapon (press F for main menu):\n1. Training rod: ")
#User choice
if weaponchoice == "1":
print("The amount of training rods needed for next magic level is " + str((nextmaglvlpalwithdummy(num1))) + ".")
elif weaponchoice == "f" or weaponchoice == "F":
goToMainMenu = True
break
添加回答
举报
