我的代码是:$result = 20201601; //fetched from a source as string//Convert string to date format 'Y/m/d'$date1 = substr($result, 0, 4) . '/' . substr($result, 4, 2) . '/' . substr($result, 6, 2); echo $date1 . "<br>";//Add 30 days to it$date2 = date('Y/m/d', strtotime('+30 days', strtotime($date1)));echo $date2;if ($date2 < date('Y/m/d', strtotime('now'))){ //If date fetched ($result) is older than 30 days from today's date, then fetch new date from source}代码未能在: 添加 30 天date('Y/m/d', strtotime('+30 days', strtotime($date1))),它给出:1970/01/30
1 回答
翻阅古今
TA贡献1780条经验 获得超5个赞
改变
$date1 = substr($result, 0, 4) . '/' . substr($result, 4, 2) . '/' . substr($result, 6, 2);
至
$date1 = substr($result, 0, 4) . '/' . substr($result, 6, 2) . '/' . substr($result, 4, 2);
这是必需的,因为您当前的数据是 format 20201601。一个月不能有值16。
- 1 回答
- 0 关注
- 127 浏览
添加回答
举报
0/150
提交
取消
