这是我的 java 类的最后一个家庭作业，我一直试图通过编译器运行它，但我不明白代码有什么问题。在阅读了如何解决返回类型问题后，我尝试使用 void 但这只会让事情变得更糟，也许我把 void 放在了错误的地方。public class Exercise09_01 { private double width = 1; private double height = 1; public Rectangle() { } public Rectangle(double newWidth, double newHeight) { width = newWidth; height = newHeight; } public double getArea() { return width * height; } public double getPerimeter() { return 2 * (width + height); } public static void main(String[] args) { Rectangle rectangle1 = new Rectangle(4, 40); System.out.println("The area of a 4.0 x 40.0 Rectangle is " + rectangle1.getArea()); System.out.println("The perimeter of a 4.0 x 40.0 Rectangle is " + rectangle1.getPerimeter()); Rectangle rectangle2 = new Rectangle(3.5, 35.9); System.out.println("The area of a 3.5 x 35.9 Rectangle is " + rectangle2.getArea()); System.out.println("The perimeter of a 3.5 x 35.9 Rectangle is " + rectangle2.getPerimeter()); }}这是我这门课的最后一个家庭作业，我只想在任何帮助下完成它，我们将不胜感激。
4 回答
哆啦的时光机
TA贡献1779条经验 获得超6个赞
构造函数名称应与类名同名
public class Exercise09_01 {
private double width = 1;
private double height = 1;
public Exercise09_01() {
}
public Exercise09_01(double newWidth, double newHeight) {
width = newWidth;
height = newHeight;
}
}
慕村9548890
TA贡献1884条经验 获得超4个赞
public class Exercise09_01 {
private double width = 1;
private double height = 1;
public Exercise09_01() {
}
public Exercise09_01(double newWidth, double newHeight) {
width = newWidth;
height = newHeight;
}
public double getArea() {
return width * height;
}
public double getPerimeter() {
return 2 * (width + height);
}
public static void main(String[] args) {
Exercise09_01 rectangle1 = new Exercise09_01(4, 40);
System.out.println("The area of a 4.0 x 40.0 Rectangle is " + rectangle1.getArea());
System.out.println("The perimeter of a 4.0 x 40.0 Rectangle is " +
rectangle1.getPerimeter());
Exercise09_01 rectangle2 = new Exercise09_01(3.5, 35.9);
System.out.println("The area of a 3.5 x 35.9 Rectangle is " + rectangle2.getArea());
System.out.println("The perimeter of a 3.5 x 35.9 Rectangle is " +
rectangle2.getPerimeter());
}
}
感谢所有帮助，这是通过编译器的代码。只是把它留在这里供未来的访客使用。
叮当猫咪
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您的代码中的错误是您的类名和构造函数名称不同。
您有两种选择，一种是将构造函数重命名为Exercise01_01或将返回类型重命名Rectangle为 void。
public class Exercise01_01 {
private double width = 1;
private double height = 1;
public Exercise01_01() {
}
public Exercise01_01(double newWidth, double newHeight) {
width = newWidth;
height = newHeight;
}
public double getArea() {
return width * height;
}
public double getPerimeter() {
return 2 * (width + height);
}
public static void main(String[] args) {
Exercise01_01 rectangle1 = new Exercise01_01(4, 40);
System.out.println("The area of a 4.0 x 40.0 Rectangle is " + rectangle1.getArea());
System.out.println("The perimeter of a 4.0 x 40.0 Rectangle is " + rectangle1.getPerimeter());
Exercise01_01 rectangle2 = new Exercise01_01(3.5, 35.9);
System.out.println("The area of a 3.5 x 35.9 Rectangle is " + rectangle2.getArea());
System.out.println("The perimeter of a 3.5 x 35.9 Rectangle is " + rectangle2.getPerimeter());
}
}
慕桂英3389331
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public Rectangle() {
}
就Java而言，这是一种方法。所有的方法都必须有一个返回类型。
public Rectangle(double newWidth, double newHeight) {
width = newWidth;
height = newHeight;
}
和这里一样。
你真的不需要第一个，除非你真的需要能够在没有设置这些值的情况下制作一个。
您可以重命名它们，但您可能只想重命名类Rectangle
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