比较 rpy2 中的方法

Question

我有一个 rpy2 脚本：from rpy2.robjects.packages import importrbinom = importr('binom')from rpy2 import robjectsrobjects.r('''library(binom)p = seq(0,1,.01)coverage = binom.coverage(p, 10, method="bayes", type = "central")$coverage''')我想用它来比较方法列表的结果：methods = [("bayes", type = "central"),("asymptotic")]for method in methods:    robjects.globalenv["method"] = robjects.r(method)    robjects.r('''library(binom)    p = seq(0,1,0.01)    coverage = binom.coverage(p, 10, method=method)$coverage    ''')第一行给了我：invalid syntax我想包括贝叶斯方法的“类型”，但是当我删除它以获取列表中的语法时，我仍然收到错误消息：object 'bayes' not found 

Answer 1

robjects.r()收到一个字符串，因此对于此特定任务，您只需将单词 method 替换为正确的字符串即可。使用两个引号（单引号和双引号）就可以解决问题，因为.replace()会丢弃外部引号并替换文本，同时保留单引号。

from rpy2.robjects.packages import importr

binom = importr('binom')

from rpy2 import robjects

methods = ["'bayes', type='central'","'asymptotic'"]

for method in methods:

    r_string = """library(binom)

    p = seq(0,1,0.01)

    coverage = binom.coverage(p, 10, method=TECHNIQUE)$coverage

    """.replace('TECHNIQUE',method)

    robjects.r(r_string)