通过调节另一个对象属性来访问对象数组中的对象值

Question

这行得通，但问题是我可以一次性将naziv.valuein保存在 this 中，这样我就不必声明另一个变量了吗？var nazivfind methodvar naziv = obj.find(c => c.name === "naziv"); console.log(naziv.value)当前输出是应该的test， console.log(naziv.value)我想只是console.log(naziv)var obj = [{    name: "naziv",    value: "test"  },  {    name: "zzz",    value: "xxx"  }]var naziv = obj.find(c => c.name === "naziv");console.log(naziv.value)编辑：如果名称相同，还要制作一个数组或值，例如：var obj = [{    name: "naziv",    value: "test"  },  {    name: "zzz",    value: "xxx"  },  {    name: "Telefon[]",    value: "tel1"  }, {    name: "Telefon[]",    value: "tel2"  }]var naziv = obj.find(c => c.name === "Telefon[]");console.log(naziv.value)应该：[tel1,tel2]

Answer 1

如果您希望多个值作为一个数组，这可以是其中一种方法

var obj = [{name:"naziv",value:"test"},{name:"zzz",value:"xxx"},{name:"Telefon[]",value:"tel1"},{name:"Telefon[]",value:"tel2"}]

var naziv = obj.filter(c => c.name === "Telefon[]").map(res => res.value);

console.log(naziv)

同样，如果该值本身就是预期输出，并且如果只期望单个值，则以下是其中一种方法。在这里，我用过Optional Chaining

var obj = [{name:"naziv",value:"test"},{name:"zzz",value:"xxx"},{name:"Telefon[]",value:"tel1"}]

var naziv = obj.find(c => c.name === "Telefon[]")?.value;

console.log(naziv)

如果您需要此代码来运行某些旧版本的浏览器并且不支持，则可能有机会Optional Chaining下面是另一种方式

var obj = [{name: "naziv",value: "test"},{name: "zzz",value: "xxx"},{name: "Telefon[]",value: "tel1"}]

var naziv = (obj.find(c => c.name === "Telefon[]") || {}).value;

console.log(naziv)

var notFound = (obj.find(c => c.name === "not_found") || {}).value;

console.log(notFound);

Answer 2

var obj = [{

    name: "naziv",

    value: "test"

  },

  {

    name: "zzz",

    value: "xxx"

  },

  {

    name: "naziv",

    value: "xxx"

  }

]

var naziv = obj.filter(item => item.name === 'naziv').map(item => item.value)

console.log(naziv)

Answer 3

你可以使用像这样的解构const {value:naziv} = obj.find(c => c.name === "naziv");